JMeter JSON提取器通过条件获取价值 [英] JMeter JSON Extractor to get value by condition

问题描述

我得到这样的JSON字符串:

[{"id":123,"name":"XX","default":false,"type":"other"},{"id":789,"name":"ZZ","default":false,"type":"first"}]

我想获取id，其中名称为ZZ，因此提取的值应为789. 我尝试使用以下JSON表达式:

I would like to get id, where name is ZZ, so extracted value should be 789. I tried with this JSON expression:

$.id[?(@.name=='ZZ')]

我也尝试过使用正则表达式:

I tried with regular expression too:

{"id":(.+?),"name":"ZZ","default":false，

我的正则表达式解决方案无法正常工作，因为有相似的name值，例如ZZ和ZZ (XYZ).

My regular expression solution isn't working, because there are similar name values, like ZZ and ZZ (XYZ).

推荐答案

您很近，使用JSON提取器，您需要找到ZZ，然后获取对象返回的ID，请使用以下表达式:

You were close, with JSON extractor you need to find ZZ and then get the id of the object return, use the following expression:

[?(@.name == 'ZZ')].id

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