Google Mock:为什么NiceMock不忽略意外呼叫? [英] Google Mock: why NiceMock does not ignore unexpected calls?

问题描述

我将Google Mock 1.7.0与Google Test 1.7.0一起使用.问题是，当我使用NiceMock时，由于意外的模拟函数调用(根据Google Mock文档应被NiceMock忽略)而导致测试失败. 代码如下:

I am using Google Mock 1.7.0 with Google Test 1.7.0. The problem is when I use NiceMock I get test failures because of unexpected mock function call (which should be ignored by NiceMock as per Google Mock documentation). The code looks like this:

// Google Mock test

#include <gtest/gtest.h>
#include <gmock/gmock.h>

using ::testing::Return;
using ::testing::_;

class TestMock {
public:
  TestMock() {
    ON_CALL(*this, command(_)).WillByDefault(Return("-ERR Not Understood\r\n"));
    ON_CALL(*this, command("QUIT")).WillByDefault(Return("+OK Bye\r\n"));
  }
  MOCK_METHOD1(command, std::string(const std::string &cmd));
};

TEST(Test1, NiceMockIgnoresUnexpectedCalls) {
  ::testing::NiceMock<TestMock> testMock;
  EXPECT_CALL(testMock, command("STAT")).Times(1).WillOnce(Return("+OK 1 2\r\n"));
  testMock.command("STAT");
  testMock.command("QUIT");
}

但是当我运行测试时，它失败并显示以下消息:

But when I run the test it fails with the following message:

[ RUN      ] Test1.NiceMockIgnoresUnexpectedCalls
unknown file: Failure

Unexpected mock function call - taking default action specified at:
.../Test1.cpp:13:
    Function call: command(@0x7fff5a8d61b0 "QUIT")
          Returns: "+OK Bye\r\n"
Google Mock tried the following 1 expectation, but it didn't match:

.../Test1.cpp:20: EXPECT_CALL(testMock, command("STAT"))...
  Expected arg #0: is equal to "STAT"
           Actual: "QUIT"
         Expected: to be called once
           Actual: called once - saturated and active
[  FAILED  ] Test1.NiceMockIgnoresUnexpectedCalls (0 ms)

是我误解或做错了什么，还是Google Mock框架中的错误?

It there something that I misunderstand, or doing wrong, or that is a bug in Google Mock framework?

推荐答案

仅当在方法上未设置期望时，NiceMock和StrictMock之间的区别才起作用.但是您已经告诉Google Mock期望使用参数"QUIT"一次调用command.看到第二个电话时，就会抱怨.

Distinctions between NiceMock and StrictMock only come into play if there are no expectations set on the method. But you you have told Google Mock to expect a single call to command with the argument "QUIT". When it sees the second call, it complains.

也许你是这个意思:

EXPECT_CALL(testMock, command("STAT")).Times(1).WillOnce(Return("+OK 1 2\r\n"));
EXPECT_CALL(testMock, command("QUIT"));

这将导致两次调用-一次使用"STAT"作为参数，一次使用"QUIT".或这样:

which will expect two calls - one with "STAT" as a parameter, and one with "QUIT". Or this:

EXPECT_CALL(testMock, command(_));
EXPECT_CALL(testMock, command("STAT")).Times(1).WillOnce(Return("+OK 1 2\r\n"));

，它将期望使用参数"STAT"的单个请求，以及使用参数"STAT"以外的参数的另一个调用.在这种情况下，期望的顺序很重要，因为EXPECT_CALL(testMock, command(_))可以满足任何调用，包括"STAT"的调用(如果它在另一个期望之后).

which will expect a single one with the parameter "STAT" and one other call with a parameter other than "STAT". The order of expectations in this case is important as EXPECT_CALL(testMock, command(_)) will satisfy any calls, including the one with "STAT" if it comes after the other expectation.

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