使用正则表达式根据用户名的最终字母更改文本 [英] Changing text based on the final letter of user name using regular expression

问题描述

我希望根据用例更改用户名的结尾(在语言系统将运行的情况下，名称的结尾取决于使用方式).

I am looking to change the ending of the user name based on the use case (in the language system will operate, names ends depending on how it is used).

因此需要定义名称的所有结尾并定义它们的替换. 建议使用.gsub正则表达式搜索和替换字符串:

So need to define all endings of names and define the replacement for them. Was suggested to use .gsub regular expression to search and replace in a string:

根据用户的最终字母更改文本名称

"name surname".gsub(/e\b/, 'ai')

这将用ai替换e，所以姓氏= namai surnamai".

this will replace e with ai, so "name surname = namai surnamai".

如何在同一记录中将其用于更多选项，例如:"e = ai，us = mi，i = as"?

How can it be used for more options like: "e = ai, us = mi, i = as" on the same record?

谢谢

推荐答案

您可以将String#gsub与block一起使用. 文档说:

You can use String#gsub with block. Docs say:

以块形式，将当前的匹配字符串作为参数传递，并且将适当设置变量，例如$ 1，$ 2，$`，$&和$'.该块返回的值将替换为每次调用时的匹配项.

In the block form, the current match string is passed in as a parameter, and variables such as $1, $2, $`, $&, and $' will be set appropriately. The value returned by the block will be substituted for the match on each call.

因此，您可以将正则表达式与要替换的所有子字符串串联使用，然后在块中替换它，例如使用将匹配项映射到替换项的哈希值.

So you can use a regex with concatenation of all substrings to be replaced and then replace it in the block, e.g. using a hash that maps matches to replacements.

完整示例:

replacements = {'e'=>'ai', 'us'=>'mi', 'i' => 'as'}
['surname', 'surnamus', 'surnami'].map do |s| 
  s.gsub(/(e|us|i)$/){|p| replacements[p] }
end

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