R:控制直方图箱数 [英] R: Control number of histogram bins

问题描述

我正在使用历史函数分析我生成的一些数据.对于分析测定，我想精确控制直方图箱的数量.

I am using the hist-function to analyze some data I generated. For an analysis-assay I would like to precisely control the number of histogram bins.

我知道中断参数"，并且我可以看到在许多情况下垃圾箱的数量与中断的数量成正比(即no_bins = no_breaks + 1).

I know the "break-argument" and I can see that in many cases the number of bins is in a direct relationship to the number of breaks (i.e. no_bins = no_breaks + 1).

由于R的算法并非总是如此.有没有办法强迫R输出特定数量的垃圾箱?

Due to R's algorithm this is not always the case. Is there a way to force R to output a specific number of bins?

让我知道是否需要指定更多详细信息.

Let me know if I need to specify further details.

非常感谢！

推荐答案

在?hist中，有几个选项可通过breaks参数控制垃圾箱.

From ?hist, there are several options for controlling the bins through the breaks argument.

breaks之一:

给出直方图单元格之间断点的向量

a vector giving the breakpoints between histogram cells,

用于计算断点矢量的函数

a function to compute the vector of breakpoints,

给出直方图的单元格数量的单个数字

a single number giving the number of cells for the histogram,

一个字符串，命名一个算法来计算单元数 (请参阅详细信息")，

a character string naming an algorithm to compute the number of cells (see ‘Details’),

一个计算细胞数量的函数.

a function to compute the number of cells.

在最后三种情况下，该数字仅是建议值；这 断点将被设置为漂亮的值.如果中断是一个功能，则 x向量是唯一的参数.

In the last three cases the number is a suggestion only; the breakpoints will be set to pretty values. If breaks is a function, the x vector is supplied to it as the only argument.

为了获得最高的精度，您必须通过提供断点矢量或计算它们的函数来精确设置断点.您需要用断点覆盖x的整个范围，断点比bin还要多1个(即no_bins +1 = no_breaks).

For the greatest precision, you have to set the breakpoints exactly, either by supplying a vector of breakpoints, or a function to compute them. You need to cover the entire range of x with your breakpoints and there will be 1 more breakpoint than bins (i.e. no_bins + 1 = no_breaks).

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