PHP替换HTML标记以外的字符 [英] PHP replace characters except the HTML tags

问题描述

我需要在字符串中用\xD9\xA0,\xD9\xA1,\xD9\xA2,...,\xD9\xA9替换字符0,1,2,...,9.该字符串来自CKEditor，因此它可能包含html标记.使用以下代码

I need to replace the characters 0,1,2,...,9 with \xD9\xA0,\xD9\xA1,\xD9\xA2,...,\xD9\xA9 in a string. This string comes from the CKEditor so it may contains html tags. Using the following code

$body = str_replace("1", "\xD9\xA1", $body);

它将每个1替换为\xD9\xA1，因此它会影响标签<h1>和<table border="1">，而我只需要替换正文中的数字而不是标签.

it replaces every 1 with \xD9\xA1 so it effects the tag <h1> and also <table border="1"> while I only need to replace the numbers in the body not the tags.

包含数字的标签是表标签的<h0><h1><h2><h3><h4><h5><h6>和cellspacing以及cellpadding和border.

The tags that contain numbers are <h0><h1><h2><h3><h4><h5><h6> and cellspacing and cellpadding and border of table tag.

在不影响<h0><h1><h2><h3><h4><h5><h6>和cellspacing和cellpadding和border的情况下，如何用上述符号替换数字?

How do I can replace the numbers with the above symbols while it won't effect the <h0><h1><h2><h3><h4><h5><h6>and cellspacing and cellpadding and border ?

推荐答案

您不应使用正则表达式来处理html，但是，如果您仍想使用正则表达式，则可以将丢弃模式与正则表达式一起使用，如下所示:

You shouldn't use regex to process html, however if you still want to use a regex you could use the discard pattern with a regex like this:

<.*?>(*SKIP)(*FAIL)|1

工作演示

Working demo

此正则表达式背后的想法是跳过<...>中的所有内容，但将其余部分匹配.因此，它将仅与不在html标记内的数字1匹配.再一次，我将使用html解析器代替.

The idea behind this regex is to skip whatever it is within <...> but match the rest. So, it will only match the number 1 that are not within html tags. Once again, I'd use a html parser instead.

Php代码

$re = "/<.*?>(*SKIP)(*FAIL)|1/"; 
$str = "<h0><h1><h2><h3>\n<table border=\"1\">\n1\n"; 
$subst = "\xD9\xA1"; 

$result = preg_replace($re, $subst, $str);

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