PHP Token 替换 html 实体 [英] PHP Token replaces html entities

问题描述

如果在文本中找到某些单词/字符串，我想制作链接之类的.我有一段来自 php.bet 的代码可以做到这一点，但它也从 <a href="http://www.domain.com/index.php" title= 中删除了标签的开头和结尾主页">转到主页.你能帮忙解决这个问题吗?

I want to make certain words/strings like links if found in the text. I have a piece of code from php.bet which does that, but it also removes the beginning and end of tags from <a href="http://www.domain.com/index.php" title="Home">go to homepage</a>. Can you help solve this?

代码如下:

<?php

$str_in =   '<p>Hi there worm! You have a disease!</p><a href="http://www.domain.com/index.php" title="Home">go to homepage</a>';
$replaces=      array(
                'worm' => 'http://www.domain.com/index.php/worm.html',
                'disease' => 'http://www.domain.com/index.php/disease.html'
                );

function addLinks($str_in, $replaces)
{
  $str_out = '';
  $tok = strtok($str_in, '<>');
  $must_replace = (substr($str_in, 0, 1) !== '<');
  while ($tok !== false) {
    if ($must_replace) {
      foreach ($replaces as $tag => $href) {
        if (preg_match('/\b' . $tag . '\b/i', $tok)) {
          $tok = preg_replace(
                                '/\b(' . $tag . ')\b/i',
                                '<a title="' . $tag . '" href="' . $href . '">\1</a>',
                                $tok,
                                1);
          unset($replaces[$tag]);
        }
      }
    } else {
      $tok = "<$tok>";
    }
    $str_out .= $tok;
    $tok = strtok('<>');
    $must_replace = !$must_replace;
  }
  return $str_out;
}

echo addLinks($str_in, $replaces);

结果是:

蠕虫！你有病！

a href="http://www.domain.com/index.php" title="首页"/a

a href="http://www.domain.com/index.php" title="Home"/a

将蠕虫"和疾病"词转换为所需的链接，但其余...

The "worm" and "disease" words are transformed into links like desired, but the rest...

非常感谢！

推荐答案

这对函数应该可以做你想做的没有用正则表达式解析 HTML 带来的问题 或 str_replace.

This pair of functions should do what you want without the problems that come with parsing HTML with regex or str_replace.

function process($node, $replaceRules)
{
    if($node->hasChildNodes()) {
        $nodes = array();
        foreach ($node->childNodes as $childNode) {
            $nodes[] = $childNode;
        }
        foreach ($nodes as $childNode) {
            if ($childNode instanceof DOMText) {
                $text = preg_replace(
                    array_keys($replaceRules),
                    array_values($replaceRules),
                    $childNode->wholeText);
                $node->replaceChild(new DOMText($text),$childNode);
            }
            else {
                process($childNode, $replaceRules);
            }
        }
    }
}

function addLinks($str_in, $replaces)
{
    $replaceRules = array();    
    foreach($replaces as $k=>$v) {
        $k = '/\b(' . $k . ')\b/i';
        $v = '<a href="' . $v . '">$1</a>';
        $replaceRules[$k] = $v;
    }

    $doc = new DOMDocument;
    $doc->loadHTML($str_in);
    process($doc->documentElement, $replaceRules);
    return html_entity_decode($doc->saveHTML());
}

注意:如果 HTML 结构不合理，无需担心(如您的示例所示)；但是，输出将结构良好.

Note: No need to worry if the HTML is not well structured (as in your example); however, the output will be well structured.

应得的信用:递归 process() 函数执行大部分实际工作，直接来自 Lukáš Lalinský 对 如何替换 HTML 中的文本.addLinks() 函数只是针对您的问题量身定制的用例.

Credit where it’s due: The recursive process() function, which does most of the real work, comes direclty from Lukáš Lalinský’s answer to How to replace text in HTML. The addLinks() function is just a use case tailored to fit your question.

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