检查十六进制值列表是否连续 [英] Check whether a list of hexadecimal values is sequential or not

问题描述

想要一个函数/语句，以检查mylist的所有值是否都是顺序的，即十六进制列表. 例如:

Want a function / statement, to check whether all the values of mylist are sequential or not, which is hexadecimal list. For example:

def checkmylist(mylist):
    #code returns True or False


mylist1 = ['03', '04', '05', '06', '07', '08', '09', '0a', '0b', '0c','0d', '0e', '0f']
mylist2 = ['03', '05', '06', '07', '08', '09', '0a', '0b', '0c','0d', '0e', '0f']

checkmylist(mylist1)
#expected to returns pass
checkmylist(mylist2)
#expected to returns fail

推荐答案

def checkmylist(mylist):
    it = (int(x, 16) for x in mylist)
    first = next(it)
    return all(a == b for a, b in enumerate(it, first + 1))

在第一个语句中，我们将十六进制数字转换为整数生成器.使用next(it)，我们将生成器的第一个元素.然后，列举从first + 1开始编号的其余元素.我们得出的结论是，如果每个元素的编号与元素本身的编号相同，我们将获得一个顺序列表.

With the first statement we convert the hex numbers to a generator of integers. With next(it) we take the first element of the generator. Then we enumerate the rest of the elements starting the numbering from first + 1. We conclude that we have a sequential list if the numbering of each element is the same as the element itself.

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