使用Jackson将Java对象转换为JSON字符串时如何取消UNESCAPE字符串 [英] How to UNESCAPE String while converting java object to JSON string using Jackson

问题描述

我正在使用Jackson 2.4.3版将复杂的Java对象转换为String对象，因此下面是我得到的输出.输出如下(Fyi - I just printed some part of output)

I am using Jackson version 2.4.3 for converting my complex Java object into String object, so below is what I'm getting in output. The output getting like below (Fyi - I just printed some part of output)

"{\"FirstName\":\"John \",\"LastName\":cena,\"salary\":7500,\"skills\":[\"java\",\"python\"]}";

这是我的代码(PaymentTnx是复杂的Java对象)

Here is my code (PaymentTnx is complex Java object)

ObjectMapper mapper = new ObjectMapper();
mapper.setVisibility(PropertyAccessor.FIELD, Visibility.ANY);
String lpTransactionJSON = mapper.writeValueAsString(paymentTxn);

我不想在我的JSON字符串中看到\斜线.我需要做什么 ?如下所示:

I don't wanted to see \ slashesh in my JSON string. What I need to do ? Like below:

"{"FirstName":"John ","LastName":cena,"salary":7500,"skills":["java","python"]}";

推荐答案

String test = "{\"FirstName\":\"John \",\"LastName\":cena,\"salary\":7500,\"skills\":[\"java\",\"python\"]}";
        System.out.println(StringEscapeUtils.unescapeJava(test));

这可能会对您有所帮助.

This might help you.

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