如何使用 Java/Jackson 取消转义 JSON 字符串? [英] How do I unescape a JSON String using Java/Jackson?

问题描述

我使用 Jackson 2.4.3 版将复杂的 Java 对象转换为 String 对象，下面是我在输出中得到的内容.输出如下(仅供参考 - 我只是打印了输出的一部分)

I am using Jackson version 2.4.3 for converting my complex Java object into a String object, so below is what I'm getting in output. The output is like below (Fyi - I just printed some part of the output)

"{"FirstName":"John ","LastName":cena,"salary":7500,"skills":["java","python"]}";

这是我的代码(PaymentTnx 是一个复杂的 Java 对象)

Here is my code (PaymentTnx is a complex Java object)

ObjectMapper mapper = new ObjectMapper();
mapper.setVisibility(PropertyAccessor.FIELD, Visibility.ANY);
String lpTransactionJSON = mapper.writeValueAsString(paymentTxn);

我不想在我的 JSON 字符串中看到 斜线.我需要做什么才能获得如下所示的字符串:

I don't want to see slashes in my JSON string. What do I need to do to get a string like below:

"{"FirstName":"John ","LastName":cena,"salary":7500,"skills":["java","python"]}";

推荐答案

String test = "{"FirstName":"John ","LastName":cena,"salary":7500,"skills":["java","python"]}";
        System.out.println(StringEscapeUtils.unescapeJava(test));

这可能对你有帮助.

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