正则表达式匹配所有不以数字开头的单词 [英] Regex to match all words not starting with digit

问题描述

很抱歉提出这个笨拙的问题，但是我对正则表达式不是很热衷.我有几个这样的观点:

Sorry for the noobish questions, but i am not very keen with regex. I have several senteces like this:

text1.2text: text3,,text4 5. text6=== t7@ text8. T, 9-- T10，我想使用scanner返回:

a)个单字符， b)个包含字符和数字但以字符开头的单词.

其他任何东西都可以视为定界符.

a) single chars, b) words containing chars and digits but that do start with a char.

Anything else can be seen as a delimiter.

因此，在以上观点中，应将这些内容返回:

So in the above sentece these should be returned:

text1
text3
text4
text6
t7
text8
T
T10

我可以在扫描仪中使用多个定界符，例如"\\.|\\:|\\,|\\,,"等，但是它可能是我要提取的单词之间的任何内容，但无论如何我都不是一个很好的方法.

I could use multiple delimiters in scanner like "\\.|\\:|\\,|\\,," etc but it could be anything in between the words i want to extract plus i do not this its a very good way to do it anyway.

我是否可以使用正则表达式作为定界符或在scanner.hasNext("regex")中提取这些单词?

Is there a regex i can use as a delimiter or maybe in scanner.hasNext("regex") to extract those words?

预先感谢

推荐答案

我不确定这是否是您的意思，但似乎您想将以下部分用作分隔符:

I am not sure if that is what you mean, but it seems that you want to use as delimiters these parts:

text1.2text:  text3,,text4 5. text6=== t7@ text8. T, 9-- T10
     ^^^^^^^^^     ^^     ^^^^     ^^^^  ^^     ^^ ^^^^^^

这意味着您想在每个非字母数字字符(以及以其开头的数字开头的可选单词)上分割此字符串.如果是这种情况，您可以将扫描仪设置为使用定界符，例如

which means that you want to split this string on every non-alphanumeric-characters (and optional words starting with number after it). If that is the case you can set up your scanner to use delimiter like

"([^\\w]+(\\d\\w*)*)+"

• [^\\w]+一个或多个非字母数字字符
• (\\d\\w*)*，后跟零个或多个以数字开头的单词
• ([^\\w]+(\\d\\w*)*)+分隔符可以重复多次(这样，我们将避免在分隔符之间返回空字符串)
• [^\\w]+ one or more non-alphanumeric-character
• (\\d\\w*)* which can be followed by zero or more words which start with digit
• ([^\\w]+(\\d\\w*)*)+ delimiter can repeat more than once (this way we will avoid returning empty strings between delimiters)

并简单地遍历next元素.

演示:

String text = "text1.2text:  text3,,text4 5. text6=== t7@ text8. T, 9-- T10";
Scanner sc = new Scanner(text);
sc.useDelimiter("([^\\w]+(\\d\\w*)*)+");
while(sc.hasNext())
    System.out.println(sc.next());

输出:

text1
text3
text4
text6
t7
text8
T
T10

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