Python正则表达式删除所有包含数字的单词 [英] Python regex to remove all words which contains number

问题描述

我正在尝试制作一个 Python 正则表达式，它允许我删除包含数字的字符串的所有世界.

例如:

in = "ABCD abcd AB55 55CD A55D 5555"out = "ABCD abcd"

删除数字的正则表达式很简单:

print(re.sub(r'[1-9]','','Paris a55a b55 55c 555 aaa'))

但我不知道如何删除整个单词而不仅仅是数字.

你能帮我吗?

解决方案

您需要正则表达式吗?你可以做类似的事情

<预><代码>>>>words = "ABCD abcd AB55 55CD A55D 5555">>>' '.join(s for s in words.split() if not any(c.isdigit() for c in s))'ABCD abcd'

如果你真的想使用正则表达式，你可以试试\w*\d\w*:

<预><代码>>>>re.sub(r'\w*\d\w*', '', words).strip()'ABCD abcd'

I am trying to make a Python regex which allows me to remove all worlds of a string containing a number.

For example:

in = "ABCD abcd AB55 55CD A55D 5555"
out = "ABCD abcd"

The regex for delete number is trivial:

print(re.sub(r'[1-9]','','Paris a55a b55 55c 555 aaa'))

But I don't know how to delete the entire word and not just the number.

Could you help me please?

解决方案

Do you need a regex? You can do something like

>>> words = "ABCD abcd AB55 55CD A55D 5555"
>>> ' '.join(s for s in words.split() if not any(c.isdigit() for c in s))
'ABCD abcd'

If you really want to use regex, you can try \w*\d\w*:

>>> re.sub(r'\w*\d\w*', '', words).strip()
'ABCD abcd'

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