扫描程序未接受其他字符串的输入并跳过它 [英] Scanner is not taking input of another string and skipping it

问题描述

为什么扫描仪不接受另一个字符串的输入并跳过它?我不明白，这是我的代码:

Why scanner is not taking input of another string and skepping it? I cant understand, here is my code:

import java.util.Scanner;

public class demo {

    public static void main(String[] args) {

        Scanner s = new Scanner(System.in);
        String name;
        String address;
        int age;

        System.out.println("Enter your name");
        name = s.nextLine();
        System.out.println("My name is :" + name);

        System.out.println("Enter your age");
        age = s.nextInt();
        System.out.println("My age is :" + age);

        System.out.println("Enter your address");
        address = s.nextLine();
        System.out.println("My address is :" + address);
    }
}

输出:

输入您的姓名
dk
我的名字是:dk
输入您的年龄
22
我的年龄是:22
输入您的地址
我的地址是:

Enter your name
dk
My name is :dk
Enter your age
22
My age is :22
Enter your address
My address is :

推荐答案

这很简单.您可以在age = s.nextInt()之后使用s.nextLine();;

It is simple. You can use s.nextLine(); after the age = s.nextInt();

扫描程序提供了一种方法nextInt()来请求用户输入，并且不使用最后一个换行符(\n).

Scanner provides a method nextInt() to request user input and does not consume the last newline character (\n).

System.out.println("Enter your age");
age = s.nextInt();
s.nextLine(); // consumes the \n character
System.out.println("My age is :" + age);

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