验证扫描仪的输入:是否为整数且在一定数字范围内? [英] Validate input of a scanner: is it an integer and within a certain number range?
本文介绍了验证扫描仪的输入:是否为整数且在一定数字范围内?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是编程新手,目前正在学习Java类,在该类中必须验证用户的扫描器输入.下面的代码似乎可以正常工作,但是我认为它效率不高.必须有更好的方法来做到这一点!
I'm new at programming and I am currently following a Java class where I must validate a user's scanner input. The code below seems to work but I think it's a little bit inefficient. There must be a better way to do this!
欢迎您提出建议!
这就是我所拥有的:
do {
System.out.println("What is you age?");
while (!scSudoku.hasNextInt()) {
System.out.println("You must enter an number");
scSudoku.next();
}
age = scSudoku.nextInt();
if (age < 10 || age > 90) {
System.out.println("You age must be within 10 and 90");
}
} while (age < 10 || age > 90);
推荐答案
使用nextLine()
丢弃任何错误的输入.
Use nextLine()
to discard any bad input.
通过使用永无止境的循环来防止代码重复,并使用break
或return
退出循环.我更喜欢将代码隔离在辅助方法中,并使用return
.
Prevent code-duplication by using a never-ending loop, and either break
or return
to exit the loop. I prefer isolating the code in a helper method and use return
.
private static int promptAge(Scanner sc) {
System.out.println("What is you age?");
for (;;) {
if (! sc.hasNextInt()) {
System.out.println("You must enter an number");
} else {
int age = sc.nextInt();
if (age >= 10 && age <= 90)
return age;
System.out.println("You age must be within 10 and 90");
}
sc.nextLine(); // discard (rest of) line of input
}
}
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