C中的typedef数组类型 [英] typedef array type in C

问题描述

typedef int arr [10]

我了解以上声明为int [10]定义了新名称这样

I understand that the above statement defines a new name for int[10] so that

arr intArray;

等效于

int intArray[10];

但是，我对执行此操作的约定感到困惑.在我看来

However, I am confused by the convention for doing this. It seems to me that

typedef int arr [10]

令人困惑，对我来说一个清晰的方法是

is confusing and a clear way to me is

typedef int [10] arr

即我将"int [10]"定义为一种称为arr

i.e. I define the "int[10]" to be a new type called arr

但是，编译器不接受.

请问为什么?这只是C语言的约定吗?

May I ask why ? Is it just a convention for C language ?

推荐答案

非常早期的C版本没有 typedef 关键字.当它被添加到语言中时(1978年之前的某个时候)，它必须以与现有语法一致的方式来完成.

Very early versions of C didn't have the typedef keyword. When it was added to the language (some time before 1978), it had to done in a way that was consistent with the existing grammar.

在语法上，关键字 typedef 被视为存储类说明符，例如 extern 或 static ，甚至尽管它的含义完全不同.

Syntactically, the keyword typedef is treated as a storage class specifier, like extern or static, even though its meaning is quite different.

所以就像你可能写的那样:

So just as you might write:

static int arr[10];

您会写:

typedef int arr[10];

将 typedef 声明视为类似于对象声明.区别在于它创建的标识符(在这种情况下为 arr )是类型名称，而不是对象名称.

Think of a typedef declaration as something similar to an object declaration. The difference is that the identifier it creates (arr in this case) is a type name rather than an object name.

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