类型安全typedef在C ++ [英] typesafe typedef in C++

问题描述

我想在我的C ++程序中使用类似typedef来提高类型安全性。

I would like to use something like typedef in my C++ programs to enhance type safety.

例如，假设我有两个函数

As an example, suppose I have two functions

void function1(unsigned idOfType1);
void function2(unsigned idOfType2);

那么我可以错误地将idOfType2传递给function1，反之亦然。我想编译器给我一个错误在这种情况下。我知道我可以包装这些unsigned在一个结构，但然后我必须提供一个字段名称并使用。访问它们，这是有点不方便。这有什么好的方法吗？

then I can mistakenly pass idOfType2 to function1 and vice versa. I want the compiler to give me an error in this case. I am aware that I could wrap these unsigned in a struct, but then I'd have to give provide a field name and use . to access them, which is slightly inconvenient. Is there a good way around this?

编辑：据我所知 typedef 因为它只是一个类型的简写，不会用于类型检查。

As far as I know typedef will not work for this purpose as it is just a shorthand for a type and will not be used for type checking.

推荐答案

在这里帮助你。我不能立即想到一个更好的方法，但是如果你用你的包装在一个结构/类选项，你可以使用转换操作符，以消除成员方法或函数调用。

As you say, a typedef won't help you here. I can't think of a better way immediately, however if you go with your wrapping in a struct/class option you could use a conversion operator to eliminate the member method or function call.

例如：

struct WrappedType
{
    operator type()
    {
         return _value;
    }

    type _value;  
}

我不是说这是 - ）

I'm not saying this is the way to do it mind you ;-)

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