按除括号外的所有空格分割字符串 [英] Split string by all spaces except those in parentheses

问题描述

我试图像在空格上分割文本如下:

I'm trying to split text the following like on spaces:

var line = "Text (what is)|what's a story|fable called|named|about {Search}|{Title}"

但是我希望它忽略括号内的空格.这应该产生一个具有以下内容的数组:

but I want it to ignore the spaces within parentheses. This should produce an array with:

var words = ["Text", "(what is)|what's", "a", "story|fable" "called|named|about", "{Search}|{Title}"];

我知道这应该涉及带有line.match()的某种正则表达式.如果正则表达式删除括号，则加分.我知道word.replace()将在后续步骤中摆脱它们.

I know this should involve some sort of regex with line.match(). Bonus points if the regex removes the parentheses. I know that word.replace() would get rid of them in a subsequent step.

推荐答案

对特定的正则表达式模式使用以下方法(基于负超前断言):

Use the following approach with specific regex pattern(based on negative lookahead assertion):

var line = "Text (what is)|what's a story|fable called|named|about {Search}|{Title}",
    words = line.split(/(?!\(.*)\s(?![^(]*?\))/g);
  
console.log(words);

• (?！\(.*)确保分隔符 \ s 前没有大括号((包括伴随字符)
• (?！[^(] *?\))确保分隔符 \ s 后没有大括号)(包括服务员角色)

• (?!\(.*) ensures that a separator \s is not preceded by brace ((including attendant characters)
• (?![^(]*?\)) ensures that a separator \s is not followed by brace )(including attendant characters)

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