迅速等待异步任务 [英] Swift wait for async task

问题描述

在后台线程中，我们有:

In a background thread we have:

defer {
    cleanup()
}

loadData()

if error {
    return
}

processData()

DispatchQueue.main.asyncAfter(deadline: delay) {  //Delay = now + 0-2 seconds
     updateUI()
}

问题是我们要确保延迟 cleanUp()代码在 updateUI()之后运行.就目前而言，这不会发生，因为 updateUI()运行异步.

The problem is we want to ensure that the defer cleanUp() code runs after updateUI(). And as it stands this won't happen as updateUI() runs async.

我的想法是在该延迟时间内睡眠/阻止，而不是异步运行.完成 updateUI()后，这将延迟运行 cleanUp().

My thought was to sleep/block for that delay period instead of running asynchronously. This would have the defer cleanUp() run once updateUI() is done.

您该怎么做?还是有更好的方法?

How can you do this? Or is there a better way?

推荐答案

意识到我可以更改代码的结构:

Realized I could just change the structure of the code:

loadData()

if error {
    log.error("Error")
} else {
   processData()
}

DispatchQueue.main.asyncAfter(deadline: delay) {  //Delay = now + 0-2 seconds
  updateUI()
  cleanup()
}

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