如何在shell脚本中解析json响应? [英] How to parse json response in the shell script?

问题描述

我正在使用bash shell脚本.我需要使用shell脚本执行URL，然后解析来自其中的json数据.

I am working with bash shell script. I need to execute an URL using shell script and then parse the json data coming from it.

这是我的URL- http://localhost:8080/test_beat ，点击URL后我得到的响应将来自这两个-

This is my URL - http://localhost:8080/test_beat and the responses I can get after hitting the URL will be from either these two -

{"error": "error_message"}
{"success": "success_message"}

下面是我的shell脚本，该脚本使用wget执行URL.

Below is my shell script which executes the URL using wget.

#!/bin/bash

DATA=$(wget -O - -q -t 1 http://localhost:8080/test_beat)
#grep $DATA for error and success key

现在，我不确定如何解析$ DATA中的json响应并查看密钥是成功还是错误.如果键是成功的，那么我将打印一条消息成功"并打印$ DATA值，并退出状态代码为零的shell脚本，但是如果键是错误的话，我将打印错误"并打印$ DATA值并以非零状态代码退出shell脚本.

Now I am not sure how to parse json response in $DATA and see whether the key is success or error. If the key is success, then I will print a message "success" and print $DATA value and exit out of the shell script with zero status code but if the key is error, then I will print "error" and print $DATA value and exit out of the shell script with non zero status code.

如何解析json响应并在shell脚本中从中提取密钥?

How can I parse json response and extract the key from it in shell script?

我不想安装任何库来执行此操作，因为我的JSON响应是固定的，并且始终与上面显示的相同，因此任何更简单的方法都可以.

I don't want to install any library to do this since my JSON response is fixed and it will always be same as shown above so any simpler way is fine.

更新:-

下面是我的最终shell脚本-

Below is my final shell script -

#!/bin/bash

DATA=$(wget -O - -q -t 1 http://localhost:8080/tester)
echo $DATA
#grep $DATA for error and success key
IFS=\" read __ KEY __ MESSAGE __ <<< "$DATA"
case "$KEY" in
success)
    exit 0
    ;;
error)
    exit 1
    ;;
esac    

这看起来正确吗?

推荐答案

#!/bin/bash
IFS= read -d '' DATA < temp.txt  ## Imitates your DATA=$(wget ...). Just replace it.
while IFS=\" read -ra LINE; do
    case "${LINE[1]}" in
    error)
        # ERROR_MSG=${LINE[3]}
        printf -v ERROR_MSG '%b' "${LINE[3]}"
        ;;
    success)
        # SUCCESS_MSG=${LINE[3]}
        printf -v SUCCESS_MSG '%b' "${LINE[3]}"
        ;;
    esac
done <<< "$DATA"
echo "$ERROR_MSG|$SUCCESS_MSG"  ## Shows: error_message|success_message

  * ％b 在相应的参数中扩展反斜杠转义序列.

  * %b expands backslash escape sequences in the corresponding argument.

更新，因为我一开始并没有真正得到这个问题.它应该简单地是:

Update as I didn't really get the question at first. It should simply be:

IFS=\" read __ KEY __ MESSAGE __ <<< "$DATA"
[[ $KEY == success ]]  ## Gives $? = 0 if true or else 1 if false.

您可以进一步检查它:

case "$KEY" in
success)
    echo "Success message: $MESSAGE"
    exit 0
    ;;
error)
    echo "Error message: $MESSAGE"
    exit 1
    ;;
esac

当然可以用它进行类似的明显测试:

Of course similar obvious tests can be done with it:

if [[ $KEY == success ]]; then
    echo "It was successful."
else
    echo "It wasn't."
fi

从您最后的评论中可以很容易地完成

From your last comment it can be simply done as

IFS=\" read __ KEY __ MESSAGE __ <<< "$DATA"
echo "$DATA"  ## Your really need to show $DATA and not $MESSAGE right?
[[ $KEY == success ]]
exit  ## Exits with code based from current $?. Not necessary if you're on the last line of the script.

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