需要较早版本的Bash上的readarray/mapfile替代脚本 [英] Need alternative to readarray/mapfile for script on older version of Bash

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本文介绍了需要较早版本的Bash上的readarray/mapfile替代脚本的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

脚本为:

#!/bin/bash

# Dynamic Menu Function
createmenu () {
    select selected_option; do # in "$@" is the default
        if [ 1 -le "$REPLY" ] && [ "$REPLY" -le $(($#)) ]; then
            break;
        else
            echo "Please make a vaild selection (1-$#)."
        fi
    done
}

declare -a drives=();
# Load Menu by Line of Returned Command
mapfile -t drives < <(lsblk --nodeps -o name,serial,size | grep "sd");
# Display Menu and Prompt for Input
echo "Available Drives (Please select one):";
createmenu "${drives[@]}"
# Split Selected Option into Array and Display
drive=($(echo "${selected_option}"));
echo "Drive Id: ${drive[0]}";
echo "Serial Number: ${drive[1]}";

较旧的系统没有 mapfile readarray ,因此我需要将该行转换为可以读取 lsblk每行的另一行.代码>输出到数组中.

The older system doesn't have mapfile or readarray so I need to convert that line to some alternative that can read each line of the lsblk output into an array.

所讨论的创建数组的行是:

The line in question that creates the array is:

mapfile -t drives < <(lsblk --nodeps -o name,serial,size | grep "sd");

推荐答案

您可以遍历输入并追加到数组:

You can loop over your input and append to the array:

$ while IFS= read -r line; do arr+=("$line"); done < <(printf '%d\n' {0..5})
$ declare -p arr
declare -a arr='([0]="0" [1]="1" [2]="2" [3]="3" [4]="4" [5]="5")'

或者,对于您的具体情况:

Or, for your specific case:

while IFS= read -r line; do
    drives+=("$line")
done < <(lsblk --nodeps -o name,serial,size | grep "sd")

请参见 BashFAQ/001 ,以很好地解释 IFS =为何读-r是个好主意:它可确保保留空白且不解释反斜杠序列.

See the BashFAQ/001 for an excellent explanation why IFS= read -r is a good idea: it makes sure that whitespace is conserved and backslash sequences not interpreted.

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