带有空格的Bash多行输出，作为数组变量 [英] Bash multi-line output with spaces, as array variable

问题描述

我在Mac OS X的Bash 3.2上难以处理命令输出.我有一个输出多行字符串的命令.字符串的每一行在值中都有空格.

I'm struggling with command output on Bash 3.2 on Mac OS X. I have a command that outputs a multi-line string. Each line of the string has spaces in the value.

我想将每个值分配给数组变量的元素.

I want to assign each value to an element of an array variable.

我有以下脚本:

declare -a sublist;
sublist=`azure account list --json | jsawk 'return this.name' -a 'return this.join("\n")'`;
echo ${sublist[0]};

azure 命令的输出为:

Visual Studio Ultimate with MSDN
Microsoft Partner Network

echo 命令的值是:

Visual Studio Ultimate with MSDN Microsoft Partner Network

我正在期望 echo命令的输出是:

What I'm expecting the output of the echo command to be is:

Visual Studio Ultimate with MSDN

名为 sublist 的变量应该是一个包含两个元素的数组:

The variable named sublist should be an array, with two elements:

[0] Visual Studio Ultimate with MSDN
[1] Microsoft Partner Network

我真正挣扎的部分是将每一行，包括空格，都视为一个字符串.我已经尝试了第2行的许多变体，其中我将命令输出分配给了 sublist 变量，但没有找到一个可行的方法.

The part I'm really struggling with is getting each whole line, including its spaces, to be treated as a single string. I've tried many variations of line #2, where I assign the command output to the sublist variable, and haven't found one that works.

推荐答案

您正在声明 sublist 为数组，但您仅分配给第一个元素( sublist 和 sublist [0] 在大多数情况下是同义词.在 bash 4中，可以使用 readarray 命令:

You are declaring sublist to be an array, but you are only assigning to the first element (sublist and sublist[0] are, for the most part, synonymous). In bash 4, you can use the readarray command:

readarray -t sublist < <(azure account list --json | jsawk 'return this.name' -a 'return this.join("\n")')

在 bash 4之前，您需要一个循环来一次为每个元素分配一个:

Prior to bash 4, you would need a loop to assign each element one at a time:

while IFS= read -r line; do
    sublist+=( "$line" )
done < <(azure ...)

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