如何修复错误agrep:模式过长(具有32个字符),如果字符串中没有句号,则不会显示错误? [英] How to fix error agrep: pattern too long (has > 32 chars) it doesn't show error if there is no full stop in the string?

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问题描述

agrep给出错误 agrep:模式字符串太长(具有32个字符),而模式字符串中有一个完整的stop(.)则不然.

agrep gives the error agrep: pattern too long (has > 32 chars) when there is a full stop(.) in the pattern string but not otherwise.

我想比较(大约)两个字符串,所以我为此使用了agrep,但它给出了一个错误 agrep:pattern too long(具有&​​gt; 32个字符).但是我发现,如果模式字符串中没有句号,它不会给出错误(为什么?)

I want to compare(approximately) two strings, so I'm using agrep for that but its giving an error agrep: pattern too long (has > 32 chars) . But I found out that it doesn't give the error if there is no full stop in the pattern string(why?)

`echo "The quick brown fox jumped over the lazy dog." | agrep -c -4 "The quick brown fox jumped over the lazy dog."`

预期的输出为1,而是给出错误: agrep:模式过长(具有32个字符)

expected output is 1 instead it gives an error: agrep: pattern too long (has > 32 chars)

如果我删除句号,它将起作用:

it works if I remove the full stop:

$ echo "The quick brown fox jumped over the lazy dog." | agrep -c -4 "The quick brown fox jumped over the lazy dog"  
1

推荐答案

具有两个字符串的近似字符串匹配/模糊字符串搜索.

Approximate string matching / fuzzy string searching with two strings.

使用 agrep bash :

if agrep -1 "abc" <<< "xbc" >/dev/null; then echo "match"; else echo "no match"; fi

tre-agrep bash :

if tre-agrep -q -1 "abc" <<< "xbc"; then echo "match"; else echo "no match"; fi

两种情况下的输出:


match

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