删除重复的行仅包含特定的字符串 [英] Remove duplicate line only contain specific string

问题描述

仅在包含特定字符串的情况下，我才尝试删除重复的行.删除重复的行很容易，但是一些有用的行会用:

I try to remove duplicates lines only if contain a specific string. It's easy to remove only duplicates lines, but some useful lines is deleted with :

awk '!seen[$0]++'

或

perl -ne 'print unless $seen{$_}++'

示例:

保留包含"host_name ="
的行的第一次出现保留所有包含"plugin output ="
上面的 awk 或 Perl 命令也删除了客户端编号.

keep first occurence of lines containing "host_name="
keep all occurrences of lines containing "plugin output="
with above awk or Perl commands that delete the client number too.

我的输出命令:

host_name=Client1
plugin_output=Name : Client1 Marseille
host_name=Client1
plugin_output=Client : 168131
host_name=Client1
host_name=Client1
host_name=Client1
host_name=Client1
host_name=Client1
host_name=Client1
host_name=Client1
host_name=Client2
plugin_output=Name : Client2 Besançon
host_name=Client2
plugin_output=Client : 168131
host_name=Client2
host_name=Client2
host_name=Client2
host_name=Client2
host_name=Client2
host_name=Client2
host_name=Client2
host_name=Client2
host_name=Client3
plugin_output=Name : Client3 BRETAGNE
host_name=Client3
plugin_output=Client : 168131
host_name=Client3
host_name=Client3
host_name=Client3
host_name=Client3
host_name=Client3
host_name=Client3
host_name=Client3
host_name=Client4
plugin_output=Name : Client4
host_name=Client4
plugin_output=Client : 168131
host_name=Client4
host_name=Client4
host_name=Client4
host_name=Client4
host_name=Client4
host_name=Client4
host_name=Client4
host_name=Client5
plugin_output=Name : Client5
host_name=Client5
plugin_output=Client : 168131
host_name=Client5
host_name=Client5
host_name=Client5
host_name=Client5
host_name=Client5
host_name=Client5
host_name=Client5
host_name=Client6
plugin_output=Name : Client6
host_name=Client6
plugin_output=Client : 168131
host_name=Client6
host_name=Client6
host_name=Client6
host_name=Client6
host_name=Client6
host_name=Client6
host_name=Client6
host_name=Client6
host_name=Client7
plugin_output=Name : Client7
host_name=Client7
plugin_output=Client : 168131
host_name=Client7
host_name=Client7
host_name=Client7
host_name=Client7
host_name=Client7
host_name=Client7
host_name=Client7
host_name=Client7
host_name=Client8
plugin_output=Name : Client8
host_name=Client8
plugin_output=Client : 168131
host_name=Client8
host_name=Client8
host_name=Client8
host_name=Client8
host_name=Client8
host_name=Client8
host_name=Client8

awk/sed/perl/...之后的期望值:

Desired value after awk/sed/perl/...:

host_name=Client1
plugin_output=Name : Client1 Marseille
plugin_output=Client : 168131
host_name=Client2
plugin_output=Name : Client2 Besançon
plugin_output=Client : 168131
host_name=Client3
plugin_output=Name : Client3 BRETAGNE
plugin_output=Client : 168131
host_name=Client4
plugin_output=Name : Client4
plugin_output=Client : 168131
host_name=Client5
plugin_output=Name : Client5
plugin_output=Client : 168131
host_name=Client6
plugin_output=Name : Client6
plugin_output=Client : 168131
host_name=Client7
plugin_output=Name : Client7
plugin_output=Client : 168131
host_name=Client8
plugin_output=Name : Client8
plugin_output=Client : 168131

推荐答案

您可以使用以下awk:

You can use this awk:

awk '/^plugin_output=/ || !seen[$0]++' file
host_name=Client1
plugin_output=Name : Client1 Marseille
plugin_output=Client : 168131
host_name=Client2
plugin_output=Name : Client2 Besançon
plugin_output=Client : 168131
host_name=Client3
plugin_output=Name : Client3 BRETAGNE
plugin_output=Client : 168131
host_name=Client4
plugin_output=Name : Client4
plugin_output=Client : 168131
host_name=Client5
plugin_output=Name : Client5
plugin_output=Client : 168131
host_name=Client6
plugin_output=Name : Client6
plugin_output=Client : 168131
host_name=Client7
plugin_output=Name : Client7
plugin_output=Client : 168131
host_name=Client8
plugin_output=Name : Client8
plugin_output=Client : 168131

如果记录以 plugin_output = 开头或唯一，则打印该记录.

Which prints a record if it starts with plugin_output= or if it is unique.

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