如何在循环python中使用子字符串制作字典 [英] how to make dictionary using substrings in a loop python

问题描述

我有一个包含数百万个DNA序列的fasta文件-每个DNA序列也都有一个ID.

I have a fasta file with millions of DNA sequences - for each DNA sequence, there is an ID as well.

>seq1
AATCAG #----> 5mers of this line are AATCA and ATCAG
>seq3
AAATTACTACTCTCTA
>seq19
ATTACG #----> 5mers of this line are ATTAC and TTACG

我想做的是，如果DNA序列的长度是6，那么我将使那条线的5聚体(如代码和上面所示).因此，我无法解决的问题是，我想制作一种字典，使字典显示哪个5mers来自哪个 sequence id .

what I want to do is that if the length of DNA sequence is 6 then I make 5mers of that line (shown in the code and above). So the thing that I have could not solve is that I want to make a dictionary in a way that dictionary shows which 5mers come from which sequence id.

这是我的代码，但是已经中途了:

here is my code but it is halfway through:

from Bio import SeqIO
from Bio.Seq import Seq

with open(file, 'r') as f:
    lst = []
    dict = {}
    for record in SeqIO.parse(f, 'fasta'): #reads the fast file 
        if len(record.seq) == 6:  #considers the DNA sequence length
            for i in range(len(record.seq)):
                kmer = str(record.seq[i:i + 5])
                if len(kmer) == 5:
                    lst.append(kmer)
                    dict[record.id] = kmer  #record.id picks the ids of DNA sequences


    #print(lst)
                    print(dict)

所需的字典应如下所示:

the desired dictionary should look like:

dict = {'seq1':'AATCA', 'seq1':'ATCAG', 'seq19':'ATTAC','seq19':'TTACG'}

推荐答案

，如

using defaultdict as suggested in Make a dictionary with duplicate keys in Python by @SulemanElahi because You can't have duplicate keys in a dictionary

from Bio import SeqIO
from collections import defaultdict

file = 'test.faa'

with open(file, 'r') as f:
    dicti = defaultdict(list)
    for record in SeqIO.parse(f, 'fasta'): #reads the fast file 
        if len(record.seq) == 6:  #considers the DNA sequence length
                kmer = str(record.seq[:5])
                kmer2 = str(record.seq[1:])
                dicti[record.id].extend((kmer,kmer2))  #record.id picks the ids of DNA sequences

print(dicti)

for i in dicti:
    for ii in dicti[i]:
        print(i, '   : ', ii) 

输出:

defaultdict(<class 'list'>, {'seq1': ['AATCA', 'ATCAG'], 'seq19': ['ATTAC', 'TTACG']})
seq1    :  AATCA
seq1    :  ATCAG
seq19    :  ATTAC
seq19    :  TTACG

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