正则表达式获取字符串的后3个字符 [英] Regular expression to get last 3 characters of a string

问题描述

我想编写一个仅包含字符串最后3个字符并向其附加一些常量字符串的正则表达式.

I want to write a regular expression which will take only last 3 char of a string and append some constant string to it.

我正在使用C#.我正在尝试将正则表达式作为数据库条目.稍后在应用程序中阅读此条目，并在C#中基于正则表达式进行转换.

I am using C#. I am trying to make regular expression as database entry. Later Read this entry in application and do the transformation based on regex in C#.

类似的东西:

stringVal.Trim().Substring(0, stringVal.Trim().Length - 3) + ".ConstantValue"

推荐答案

使用此正则表达式:

.{3}$

如果您想避免在末尾留空格并可以使用捕获组(您没有精确说明语言或正则表达式的味道)，请使用

If you want to avoid spaces at end and can use capturing groups (you didn't precise the language or regex flavour), use

(.{3})\s*$

但是请注意，没有明显的理由在这里使用正则表达式而不是对字符串进行切片.

But note that there's no obvious reason to use a regex here instead of slicing the string.

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