C ++错误表达式不能用作函数 [英] C++ error expression cannot be used as function

问题描述

如何为

weekday=(day+2(month)+3(month)/5+year+year/4-year/100+year/400)/7

这样我就不会收到一条错误消息，说表达式不能用作函数"?

so that I dont get an error message saying "expression cannot be used as a function"?

#include <iostream>
using namespace std;
int main()
{
int date=0;
int month=0;
int day=0;
int year=0;
int leftover=0;
int weekday=0;

cout<<"Enter Date (ex.20140912) :";
cin>>date;

year=date/10000;
leftover=date%10000;
month=leftover/100;
day=date%100;
{
if (month==3)
    {cout<<"March "<< day<<", "<< year<<":";
        weekday=(day+2(month)+3(month)/5+year+year/4-year/100+year/400)/7;

            if (weekday==0)
                {cout<<"Saturday";
                }
            if (weekday==1)
                {cout<<"Sunday";
                }
            if (weekday==2)
                {cout<<"Monday";
                }
            if (weekday==3)
                {cout<<"Tuesday";
                }
            if (weekday==4)
                {cout<<"Wednesday";
                }

推荐答案

您需要输入一个运算符(*)进行乘法:

You need to enter an operator (*) for multiplication:

weekday=(day+2*(month)+3*(month)/5+year+year/4-year/100+year/400)/7;

如果缺少运算符，c(++)会将其解释为函数调用，其中函数名称为 2 .

If the operator is missing c(++) interprets it as a function call, wherebthe function name is e.g. 2.

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