“不能用作函数误差” [英] "cannot be used as a function error"

问题描述

我在写一个简单的程序，使用在不同的.cpp文件中找到的函数。我的所有原型都包含在头文件中。我将一些函数传递到其他函数，不知道我是否正确地做。我得到的错误是'functionname'不能用作函数。它不能使用的函数是 growthRate 函数和 estimatedPopulation 函数。数据通过输入函数（我认为是工作）输入。

I am writing a simple program that uses functions found in different .cpp files. All of my prototypes are contained in a header file. I pass some of the functions into other functions and am not sure if I am doing it correctly. The error I get is "'functionname' cannot be used as a function". The function it says cannot be used is the growthRate function and the estimatedPopulation function. The data comes in through an input function (which I do think is working).

谢谢！

strong>头文件：

header file:

#ifndef header_h
#define header_h

#include <iostream>
#include <iomanip>
#include <cstdlib>


using namespace std;

//prototypes
void extern input(int&, float&, float&, int&);
float extern growthRate (float, float);
int extern estimatedPopulation (int, float);
void extern output (int);
void extern myLabel(const char *, const char *);

#endif

growthRate函数： / p>

growthRate function:

 #include "header.h"

float growthRate (float birthRate, float deathRate, float growthrt)     
{    
    growthrt = ((birthRate) - (deathRate))
    return growthrt;   
}

estimatedPopulation函数：
$ b

estimatedPopulation function:

    #include "header.h"

int estimatedPopulation (int currentPopulation, float growthrt)
{
    return ((currentPopulation) + (currentPopulation) * (growthrt / 100);
}

main：

main:

#include "header.h"

int main ()
{
    float birthRate, deathRate, growthRate;
    char response; 
    int currentPopulation, years, estimatedPopulation;

    do //main loop
    {  
        input (currentPopulation, birthRate, deathRate, years);
        growthRate (birthRate, deathRate, growthrt);

        estimatedPopulation (currentPopulation, growthrt);
        output (estimatedPopulation (currentPopulation, growthrt));
        cout << "\n Would you like another population estimation? (y,n) ";
        cin >> response;
    }          
    while (response == 'Y' || response == 'y');

    myLabel ("5-19", "12/09/2010");   

    system ("Pause");

    return 0;
}    

推荐答案

变量名和函数名。

重命名局部变量

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