如何在R中将数据移动两个月? [英] How to shift data by a factor of two months in R?

问题描述

我想将我的全部数据下移两个月.例如，如果我的数据从1月1日开始，则我希望以与3月1日相对应的方式移动数据.同样，11月的数据将成为下一年的1月的数据.这是我的示例代码

I would like to move down my entire data by a factor of two months. For example, if my data starts on Jan 01, i want to move the data in such a way that the data corresponds to March 01. Likewise, November data would become January data for the next year. Here is my sample code

DF <- data.frame(seq(as.Date("2001-01-01"), to= as.Date("2003-12-31"), by="day"),
                     A = runif(1095, 0,10),
                     D = runif(1095,5,15))
colnames(DF) <-  c("Date", "A", "B")

我尝试了 DF $ Date<-DF $ Date + 61 ，但这将整个 data.frame 移了两个月，包括 dates-我只希望数据向下移动.

I tried DF$Date <- DF$Date + 61 but this moved the entire data.frame by a factor of two months including the dates- I just want the data to moved down.

推荐答案

我认为与自身的简单合并将在此处起作用.

I think a simple merge with itself will work here.

首先，您可以复制随机数据，

First, random data that you can reproduce,

headtail <- function(x, n = 4) { print(head(x, n=n)); print(tail(x, n=n)); }

set.seed(42)
DF <- data.frame(seq(as.Date("2001-01-01"), to= as.Date("2003-12-31"), by="day"),
                     A = runif(1095, 0,10),
                     D = runif(1095,5,15))
colnames(DF) <-  c("Date", "A", "B")
headtail(DF)
#         Date        A         B
# 1 2001-01-01 9.148060 10.049361
# 2 2001-01-02 9.370754 10.324953
# 3 2001-01-03 2.861395  5.868702
# 4 2001-01-04 8.304476 14.156014
#            Date         A         B
# 1092 2003-12-28 0.3284422  6.449250
# 1093 2003-12-29 7.7729724  7.270769
# 1094 2003-12-30 5.2614178 11.023033
# 1095 2003-12-31 2.6612188 13.923079

现在合并.我只在第一帧上使用 Date ，这样移位的 Date 会附加第二帧的数据.

Now the merge. I use just the Date on the first frame so that the shifted Date will attached the data from the second frame.

out <- merge(DF["Date"], transform(DF, Date = Date + 61),
             by = "Date", all = TRUE)
headtail(out)
#         Date  A  B
# 1 2001-01-01 NA NA
# 2 2001-01-02 NA NA
# 3 2001-01-03 NA NA
# 4 2001-01-04 NA NA
#            Date         A         B
# 1153 2004-02-27 0.3284422  6.449250
# 1154 2004-02-28 7.7729724  7.270769
# 1155 2004-02-29 5.2614178 11.023033
# 1156 2004-03-01 2.6612188 13.923079

这将保留所有数据.如果您只想直到原始帧的最后一个日期，则只需将 all = 更改为 all.x = :

That is preserving all data. If you want just up until the last date of the original frame, then just change all= to all.x=:

out <- merge(DF["Date"], transform(DF, Date = Date + 61),
             by = "Date", all.x = TRUE)
headtail(out)
#         Date  A  B
# 1 2001-01-01 NA NA
# 2 2001-01-02 NA NA
# 3 2001-01-03 NA NA
# 4 2001-01-04 NA NA
#            Date         A         B
# 1092 2003-12-28 9.7939015 14.165207
# 1093 2003-12-29 1.7047221  8.269991
# 1094 2003-12-30 0.4273437  8.041551
# 1095 2003-12-31 1.4283236  5.053276

dplyr

library(dplyr)
as_tibble(DF) %>%
  mutate(Date = Date + 61) %>%
  full_join(., select(DF, Date), by = "Date") %>%
  arrange(Date)

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