根据R中的频率排序 [英] Sort based on Frequency in R

问题描述

输入数据框的结构

ds= structure(list(MSISDN = c(800, 800, 783, 
975, 800)), .Names = "Number", row.names = c(NA, 
-5L), class = "data.frame")

需要一个简单的输出，如下所示(无法添加单个中断)

Need a simple output which looks like below (not able to add single break)

数字频率

800 3

975 1

783 1

推荐答案

从管理员程序中检出Tabyl函数.它完成了您想要的任务，再加上一点

Check out Tabyl function from janitor package. It does the task that you want plus a bit more

library(janitor)
    ds <- structure(list(MSISDN = c(800, 800, 783,975, 800)), .Names = "Number", row.names = c(NA,-5L), class = "data.frame")

    tabyl(ds$Number)

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