我可以创建一个矩形表面并在该表面上绘制文本,然后在pygame中将这些对象一起变薄吗 [英] can I create a rectangular surface and draw a text over that and blit these objects together in pygame
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问题描述
我需要创建一个矩形对象,并针对该矩形对象绘制文本,然后将这些项目在屏幕上一起显示.我正在使用pygame库来创建游戏.我对此pygame编程并不陌生.有人可以建议我使用方法吗?
I need to create a rectangular object and draw a text with respect to the rectangular object and blit these items together in the screen. I am using pygame library to create the game.I am new to this pygame programming. Can someone suggest me method if it is possible?
推荐答案
文本表面是与其他任何表面一样的表面对象.呈现文本:
A text surface is a surface object like any other surface. Render the text:
font = pygame.font.SysFont(None, 80)
text_surf = font.render('test text', True, (255, 0, 0))
创建一个表面,并在其上 blit
将文本表面:
Create a surface and blit
the text surface on it:
rect_surf = pygame.Surface((400, 100))
rect_surf.fill((0, 128, 255))
rect_surf.blit(text_surf, text_surf.get_rect(center = rect_surf.get_rect().center))
最小示例:
Minimal example:
import pygame
pygame.init()
window = pygame.display.set_mode((500, 300))
clock = pygame.time.Clock()
font = pygame.font.SysFont(None, 80)
text_surf = font.render('test text', True, (255, 0, 0))
rect_surf = pygame.Surface((400, 100))
rect_surf.fill((0, 128, 255))
rect_surf.blit(text_surf, text_surf.get_rect(center = rect_surf.get_rect().center))
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
window.fill(0)
window.blit(rect_surf, rect_surf.get_rect(center = window.get_rect().center))
pygame.display.flip()
pygame.quit()
exit()
请参阅:
See alos:
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