fps-如何通过时间除以计数以确定fps [英] fps - how to divide count by time function to determine fps

问题描述

我有一个计数器在对每一帧进行计数.我要做的是将时间除以确定程序的FPS.但是我不确定如何在python中对计时功能执行操作.

I have a counter working that counts every frame. what I want to do is divide this by time to determine the FPS of my program. But I'm not sure how to perform operations on timing functions within python.

我尝试将时间初始化为

fps_time = time.time 
fps_time = float(time.time)
fps_time = np.float(time.time)
fps_time = time()

然后计算fps，

FPS = (counter / fps_time)
FPS = float(counter / fps_time)
FPS = float(counter (fps_time))

但是我遇到的错误是对象不可调用或不支持/的操作数:'int'和'buildin functions'

But errors I'm getting are object is not callable or unsupported operand for /: 'int' and 'buildin functions'

提前感谢您的帮助！

推荐答案

• 这是一种非常简单的方法，可以在每一帧打印程序的帧速率(无需计数器):

  import time
  
  while True:
      start_time = time.time() # start time of the loop
  
      ########################
      # your fancy code here #
      ########################
  
      print("FPS: ", 1.0 / (time.time() - start_time)) # FPS = 1 / time to process loop
  

• 如果要在 x 秒内保持平均帧速率，则可以这样做(需要计数器):

• If you want the average frame rate over x seconds, you can do like so (counter needed) :

  import time
  
  start_time = time.time()
  x = 1 # displays the frame rate every 1 second
  counter = 0
  while True:
  
      ########################
      # your fancy code here #
      ########################
  
      counter+=1
      if (time.time() - start_time) > x :
          print("FPS: ", counter / (time.time() - start_time))
          counter = 0
          start_time = time.time()
  

希望有帮助！

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