如何避免Go中的初始化循环 [英] How to avoid initialization loop in Go
本文介绍了如何避免Go中的初始化循环的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
当我尝试编译此代码时:
When I try to compile this code:
package main
import (
"encoding/json"
"fmt"
"net/http"
)
func main() {
fmt.Println("Hello, playground")
}
const (
GET = "GET"
POST = "POST"
PUT = "PUT"
DELETE = "DELETE"
)
type Route struct {
Name string `json:"name"`
Method string `json:"method"`
Pattern string `json:"pattern"`
HandlerFunc http.HandlerFunc `json:"-"`
}
type Routes []Route
var routes = Routes{
Route{
Name: "GetRoutes",
Method: GET,
Pattern: "/routes",
HandlerFunc: GetRoutes,
},
}
func GetRoutes(res http.ResponseWriter, req *http.Request) {
if err := json.NewEncoder(res).Encode(routes); err != nil {
panic(err)
}
}
编译器返回以下错误消息:
the compiler returns this error message:
main.go:36: initialization loop:
main.go:36 routes refers to
main.go:38 GetRoutes refers to
main.go:36 routes
此代码的目标是当客户端应用程序在/routes
路由上执行GET请求时,以JSON返回我的API的所有路由.
The goal of this code is to return all the routes of my API in a JSON when a client application executes a GET request on the the /routes
route.
关于如何找到此问题的解决方法的任何想法?
Any idea on how can I find a clean workaround to this problem?
推荐答案
稍后在 init()
中分配值.这样将首先初始化 GetRoutes
函数,然后可以对其进行分配.
Assign the value later within init()
. This will let the GetRoutes
function be initialized first, then it can be assigned.
type Routes []Route
var routes Routes
func init() {
routes = Routes{
Route{
Name: "GetRoutes",
Method: GET,
Pattern: "/routes",
HandlerFunc: GetRoutes,
},
}
}
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