iOS-比较数组中的两个数组和对象-逻辑问题 [英] iOS - Comparing 2 Arrays and Objects in an array - Logic Issue

问题描述

我有一个 NSArray ，其中包含 Person 对象.

此人员对象包含以下内容；

 >名称>年龄>学校>地址>电话号码 

稍后，我将为此人对象设置值，例如 person.Name = @"Jemmy"; (但我将不会设置其他属性，例如年龄，学校等)./p>

我有一个名为 personArray 的 NSArray ，其中包含1000个人对象记录.现在，我需要过滤掉包含 Name Jemmy 的所有对象.我该怎么办?

我当时想做的是

  NSMutableArray * arrayThatContainAllPersonObjects = [NSMutableArray arrayWithArray:personArray];[arrayThatContainAllPersonObjects removeObjectsInArray:arrayWeAddedTheName]; 

但是，我将得到的是一个没有筛选结果的数组.无论如何，这可能不是正确的方法.我相信我们可以使用 NSSets ， UNIONS 来解决此问题.

注意:有人可能会说这是一个重复的问题，但是我对此进行了很多搜索.

解决方案

您想将NSPredicate与NSArray的 filteredArrayUsingPredicate 一起使用.像这样:

  NSArray * filteredArray = [personArrayfilteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"name = \" Jemmy \"]]]; 

I have an NSArray which contains Person objects.

This person object contains the following;

> Name 
> Age 
> School 
> Address 
> Telephone_Number

Later on i will be setting values to this person object, like person.Name=@"Jemmy"; (but i will not be setting other attributes, Age, School etc.).

I have an NSArray called personArray, and it contains 1000 person object records in it. Now i need to Filter out all the objects that contains the Name Jemmy. How can i do this ?

What i was thinking of doing is;

NSMutableArray *arrayThatContainAllPersonObjects = [NSMutableArray arrayWithArray:personArray];
[arrayThatContainAllPersonObjects removeObjectsInArray:arrayWeAddedTheName];

But, what i will get is, an array that doesn't have my filter results. Anyway this might not be the correct approach. I believe we could use NSSets, UNIONS to solve this.

note:Some might say that this is a duplicate question, but i have searched so much on this.

解决方案

You want to use an NSPredicate with NSArray's filteredArrayUsingPredicate. Something like this:

NSArray *filteredArray = [personArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"name = \"Jemmy\""]];

这篇关于iOS-比较数组中的两个数组和对象-逻辑问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！