检查列表是否是列表保持顺序的一部分并查找位置 [英] Check if List is part of List keeping order and find postion

问题描述

我需要寻找匹配点"列表"a"中的两个大于列表"b".到目前为止，我已经找到了这篇较早的文章:检查列表是否在保留列表顺序的同时是另一个列表的一部分

I need to seek the "matchingpoint" of two list where List "a" is bigger than List "b". So far I've found this earlier post: Check if a list is part of another list while preserving the list sequence

那很有帮助.但是我现在需要列表适合的地方.

That helps a lot. But I need to now, where the lists fit.

a = [3, 4, 1, 2, 4, 1, 5]
b = [4, 1, 2]

"b"适合a"但我希望将 a [1] 作为第一个匹配点，而不是 TRUE 值

"b" fits in "a" but instead of a TRUE value I would like to have a[1] as first matchingpoint

推荐答案

您可以使用

You could use next to fetch the first matching point:

a = [3, 4, 1, 2, 4, 1, 5]
b = [4, 1, 2]

starting_point = next((a[i] for i in range(len(a)) if b == a[i:i + len(b)]), -1)

print(starting_point)

输出

4

更新

如果同时需要索引和索引处的值，请返回索引而不是值，例如:

If you need both the index and the value at the index, return the index instead of the value, for example:

position = next((i for i in range(len(a)) if b == a[i:i + len(b)]), -1)

print("position", position)
print("starting point", a[position])

输出

position 1
starting point 4

请注意更改，现在是 i ，而不是 a [i]

Note the change, now is i instead of a[i]

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