创建子列表列表 [英] Create list of sublists

问题描述

我有50,000个整数的列表:

I have a list of 50,000 integers:

我想从这个大列表中创建一个子列表列表.

I want to create a list of sublists from this large list.

通过在列表中查找与列表的第一个值1,000,000不同的位置来创建子列表.

The sublist is created by finding within the list the position that has a difference with the first value of the list of 1,000,000.

下面是我的代码:

sub_pos_list = []
for i in range(0, len(pos_list)):    
    difference = pos_list[i] - pos_list[0]    
    if difference <= 1000000:
        sub_pos_list.append(pos_list[0:i])

但是，这仅抓住了前1,000,000个差额.然后，我想从列表中删除该区域，然后重新开始.

However, this only grabs the first 1,000,000 difference. I want to then delete this region from the list and start over again.

我想创建多个差异为1,000,000的子列表，然后列出这些子列表.

I want to create multiple sublists of 1,000,000 difference and then make a list of these sublists.

任何建议如何做到这一点?

Any suggestions how to do this?

推荐答案

如果我正确理解了您想要实现的目标，则可以采用以下解决方案:

If I understood correctly what You want to achieve, this is the solution:

sub_pos_list = []

last_found_pos = 0
for i in xrange(last_found_pos, len(pos_list)):
  difference = pos_list[i] - pos_list[last_found_pos]
  if difference >= 1000000:
    sub_pos_list.append(pos_list[last_found_pos:i + 1])
    last_found_pos = i

来自: pos_list = [0，5，1000000，1000005，2000005]
它会给你:
sub_pos_list == [[0，5，1000000]，[1000000，1000005，2000005]]

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