c ++互斥类成员导致编译错误 [英] c++ mutex member of class causing compilation Error

问题描述

当我向 myClass(在本例中为 mu)添加互斥锁成员时，我不确定为什么会发生这种情况:

I'm not sure why this is happening when I add a mutex member to myClass(in this example mu):

Error   C2661   "'std::tuple<
void (__thiscall MyNameSpace::myClass::* )(void),MyNameSpace::myClass>::tuple': no overloaded function takes 2 arguments include\memory 2438

namespace MyNameSpace{
class myClass{
    shared_ptr<myClass2> property;
    mutex mu;

public:
    myClass(shared_ptr<myClass2> arg):property(std::move(arg)) {

    }
     void Run(){
         ...........
         }
}
class myClass2{
public:
    myClass2(std::string str) {
        trace(str);
    }

}
       }
int main(){
shared_ptr<myClass2> new_obj(new myClass2("somthing"));
    thread(&myClass::Run, myClass(new_obj)).join();
.......other stuff.....
}

我怎样才能克服这个问题?

and How can i overcome this?

推荐答案

这是编译错误，不是内存错误.

It is a compilation error, not a memory error.

注意 std::mutex 是不可复制的.因此，包含它的类也变得不可复制.

Note that std::mutex is not copiable. So, the class containing it becomes non-copiable as well.

我猜测(因为您没有显示相关代码)您试图复制 myClass 的实例，并导致上述编译错误.

I guess (as you do not show the relevant code) that you attempt to copy an instance of myClass, and that causes the above compilation error.

特别是，您可以搜索代码中的位置，在这些位置按值传递或返回 myClass 实例.

In particular, you can search places in your code, where you pass or return myClass instances by value.

更新:正如@NathanOliver 所指出的，上面代码段中的这样一个地方是:

UPDATE: As pointed out by @NathanOliver, such a place in the above snippet is:

thread(&myClass::Run, myClass(new_obj))

在其中创建临时 myClass.

这篇关于c ++互斥类成员导致编译错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！