数组大小成员函数编译错误 [英] Array Size Member Function Compile Error

问题描述

本$ C $工作c：

int myArray[10];
    for(int i = 0; i < myArray.size(); i++)
        cout << myArray[i] << endl;

编译器错误：

错误：请求成员的大小'在'myArray的，这是无级式INT [10]|

error: request for member 'size' in 'myArray', which is of non-class type 'int [10]'|

我必须失去了一些东西明显，但我没有看到它。

I must be missing something obvious but I don't see it.

推荐答案

数组类型不是类类型，并且没有成员函数。因此，一个数组没有名为的成员函数尺寸。然而，由于阵列具有编译时固定的大小，你的知道的大小为 10 ：

Array types are not class types and don't have member functions. So an array doesn't have a member function called size. However, since arrays have compile-time fixed sizes, you know the size is 10:

for(int i = 0; i < 10; i++)
    cout << myArray[i] << endl;

当然，最好避免幻数，并把大小在一个名为常量的地方。可替代地，有一个标准的库函数，用于确定阵列型对象的长度：

Of course, it's best to avoid magic numbers and put the size in a named constant somewhere. Alternatively, there is a standard library function for determining the length of an array type object:

for(int i = 0; i < std::extent(myArray); i++)
    cout << myArray[i] << endl;

您可以，但是，使用的std ::阵列相反，它封装了一个数组类型的对象为您和确实提供了一个尺寸成员函数：

You may, however, use std::array instead, which encapsulates an array type object for you and does provide a size member function:

std::array<int, 10> myArray;
for(int i = 0; i < myArray.size(); i++)
    cout << myArray[i] << endl;

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