奇怪ç整数不平等的比较结果 [英] strange C integer inequality comparison result
问题描述
的#include<&limits.h中GT;
#包括LT&;&stdio.h中GT;
诠释主(){
长IVAL = 0;
的printf(IVAL:李%,最小:%I,最大:%I,太大:%我,太小:%I \\ N,
IVAL,INT_MIN,INT_MAX,IVAL> INT_MAX,IVAL< INT_MIN);
}
这给出了输出:
IVAL:0分:-2147483648,最大:2147483647,太大:0,太小:1
这怎么可能?
(事实上,我在CPython的2.7.3这个问题/臭虫按 getargs.c
: convertsimple
如果你看到了code,在情况下,我
,还有就是检查 IVAL< INT_MIN
这是一直对我如此。参见测试用例与源进一步引用的。)
好了,现在我测试了几个不同的编译器。 GCC /锵,编为86全部返回预期(太小:0)。意外的输出在X code工具链锵编译时的ARMv7
如果要复制:
这是确切的编译命令: /Applications/X$c$c.app/Contents/Developer/Toolchains/X$c$cDefault.xctoolchain/usr/bin/clang -arch的ARMv7 - isysroot /Applications/X$c$c.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS5.1.sdk测试int.c
这为X code 4.3.2。
我复制生成的的a.out
到我的iPhone并执行它。
如果有人有兴趣在此生成汇编code:
.section伪__TEXT,__文本,定期,pure_instructions
.section伪__TEXT,__ textcoal_nt,凝聚,pure_instructions
.section伪__TEXT,__ const_coal,凝聚
.section伪__TEXT,__ picsymbolstub4,symbol_stubs,无,16
.section伪__TEXT,__ StaticInit,定期,pure_instructions
.syntax统一
.section伪__TEXT,__文本,定期,pure_instructions
.globl _main
.align伪2
。code 16
.thumb_func _main
_主要:
推{R7,LR}
MOV R7,SP
子SP,#20
MOVW R0,#65535
MOVT R0,#32767
MOVS R1,#0
MOVT R1,#0
STR R1,[SP,#16]
STR R1,[SP,#12]
LDR r1中,[SP,#12]
LDR R2,[SP,#12]
CMP R2,R0
MOVW R0,#0
它GT
movgt R0,#1
和R0,R0,#1
LDR R2,[SP,#12]
cmn.w R2,#-2147483648
MOVW R2,#0
它LT
movlt R2,#1
和r2,R2,#1
MOV R3,SP
海峡R2,[R 3,#4]
STR R0,[R3]
MOV.W R2,#-2147483648
MVN R3,#-2147483648
MOVW R0,:lower16:(L_.str-(LPC0_0 + 4))
MOVT R0,:upper16:(L_.str-(LPC0_0 + 4))
LPC0_0:
添加R0,PC
BLX _printf
LDR R1,[SP,#16]
STR R0,[SP,#8]
MOV R0,R1
加SP,#20
POP {R7,PC} .section伪__TEXT,__ CString的,cstring_literals
L_.str:
.ascizIVAL:李%,最小:%I,最大:%I,太大:%我,太小:%I \\ N
.subsections_via_symbols
这是一个错误。有C标准没有空间太小
来是任何0以外下面是它如何工作的:
-
由于
INT_MIN
是INT
,它就会被转换成长
在通常的算术转换。这是因为长
比INT
排名较高(无一不是符号类型)。没有促销发生,因为所有的操作数都至少有INT
军衔。没有未定义或执行指定的行为被调用。 -
在转换过程中,
INT_MIN
的值是preserved。因为它正在从INT
转换为长
,它保证了长
至少INT
的价值INT_MIN
必须在preserved转换。没有未定义或执行指定的行为被调用。没有模块化转换是允许的,那些是无符号类型只。 -
比较的结果应该是
0
。
有没有为符号扩展或其他类似的东西回旋余地。另外,由于在调用 printf的
是正确的,是没有问题的存在。
如果你能重现它在另一个系统上,或将其发送给其他人谁可以复制它,你应该直接报告错误到你的工具链供应商。
尝试重现错误:我无法重现下列任何组合的行为,全部都与上下车优化:
- GCC 4.0,PPC + PPC64
- GCC 4.2,PPC + PPC64
- GCC 4.3,64
- GCC 4.4,64
- 铛3.0,64
#include <limits.h>
#include <stdio.h>
int main() {
long ival = 0;
printf("ival: %li, min: %i, max: %i, too big: %i, too small: %i\n",
ival, INT_MIN, INT_MAX, ival > INT_MAX, ival < INT_MIN);
}
This gives the output:
ival: 0, min: -2147483648, max: 2147483647, too big: 0, too small: 1
How is that possible?
(I actually got hit by this problem/bug in CPython 2.7.3 in getargs.c
:convertsimple
. If you look up the code, in case 'i'
, there is the check ival < INT_MIN
which was always true for me. See also the test case source with further references.)
Well, I tested a few different compilers now. GCC/Clang, compiled for x86 all return the expected (too small: 0). The unexpected output is from the Clang in the Xcode toolchain when compiled for armv7.
If you want to reproduce:
This is the exact compile command: /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/clang -arch armv7 -isysroot /Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS5.1.sdk test-int.c
This is Xcode 4.3.2.
I copied the resulting a.out
over to my iPhone and executed it.
If anyone is interested in the assembler code generated by this:
.section __TEXT,__text,regular,pure_instructions
.section __TEXT,__textcoal_nt,coalesced,pure_instructions
.section __TEXT,__const_coal,coalesced
.section __TEXT,__picsymbolstub4,symbol_stubs,none,16
.section __TEXT,__StaticInit,regular,pure_instructions
.syntax unified
.section __TEXT,__text,regular,pure_instructions
.globl _main
.align 2
.code 16
.thumb_func _main
_main:
push {r7, lr}
mov r7, sp
sub sp, #20
movw r0, #65535
movt r0, #32767
movs r1, #0
movt r1, #0
str r1, [sp, #16]
str r1, [sp, #12]
ldr r1, [sp, #12]
ldr r2, [sp, #12]
cmp r2, r0
movw r0, #0
it gt
movgt r0, #1
and r0, r0, #1
ldr r2, [sp, #12]
cmn.w r2, #-2147483648
movw r2, #0
it lt
movlt r2, #1
and r2, r2, #1
mov r3, sp
str r2, [r3, #4]
str r0, [r3]
mov.w r2, #-2147483648
mvn r3, #-2147483648
movw r0, :lower16:(L_.str-(LPC0_0+4))
movt r0, :upper16:(L_.str-(LPC0_0+4))
LPC0_0:
add r0, pc
blx _printf
ldr r1, [sp, #16]
str r0, [sp, #8]
mov r0, r1
add sp, #20
pop {r7, pc}
.section __TEXT,__cstring,cstring_literals
L_.str:
.asciz "ival: %li, min: %i, max: %i, too big: %i, too small: %i\n"
.subsections_via_symbols
This is an error. There is no room in the C standard for too small
to be anything other than 0. Here's how it works:
Since
INT_MIN
is anint
, it gets converted tolong
during the "usual arithmetic conversions". This happens becauselong
has higher rank thanint
(and both are signed types). No promotions occur, since all of the operands have at leastint
rank. No undefined or implementation-specified behavior is invoked.During conversion, the value of
INT_MIN
is preserved. Since it is being converted fromint
tolong
, and it is guaranteed thatlong
has at least the range ofint
, the value ofINT_MIN
must be preserved during the conversion. No undefined or implementation-specified behavior is invoked. No modular conversions are permitted, those are for unsigned types only.The result of the comparison should be
0
.
There is no wiggle room for sign extension or other such things. Also, since the call to printf
is correct, there is no problem there.
If you can reproduce it on another system, or send it to someone else who can reproduce it, you should report the bug directly to your toolchain vendor.
Attempts to reproduce the bug: I was not able to reproduce the behavior on any of the following combinations, all both with optimization on and off:
- GCC 4.0, PPC + PPC64
- GCC 4.2, PPC + PPC64
- GCC 4.3, x64
- GCC 4.4, x64
- Clang 3.0, x64
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