不兼容的指针类型用“NSArray *"类型的表达式初始化“NSMutableArray *" [英] Incompatible pointer types initializing 'NSMutableArray *' with an expression of type 'NSArray *'

问题描述

这是我的代码导致上述警告:

This is my code that is causing the above warning:

    NSMutableArray *tbValueArray = [NSArray arrayWithObjects:oServices1.text,
                oServices2.text,oServices3.text,oServices4.text,oServices5.text,oServices6.text,
                oServices7.text,oServices8.text,oServices9.text,oServices10.text,oServices11.text,
                oServices12.text,oServices13.text,oServices14.text,oServices15.text,oServices16.text,
                oServices17.text,oServices18.text,oServices19.text,oServices20.text,oServices21.text,
                oServices22.text,oServices23.text,oServices24.text,nil];

我该如何更改以消除警告?(我查看了 Google 和 SO 并没有发现任何适用的内容).

How do I change this to remove the warning? (I have looked at Google and SO and found nothing that applies).

推荐答案

您是要创建 NSMutableArray 还是 NSArray?您已将变量声明为 NSMutableArray* 类型，但右侧的表达式创建了一个 NSArray.如果你希望这个数组是可变的，请将 arrayWithObjects: 的接收者更改为 NSMutableArray;如果不是，请更改声明以将其正确标识为 NSArray 而不是 NSMutableArray.

Are you trying to create an NSMutableArray or an NSArray? You have declared the variable as being of type NSMutableArray*, but the expression on the right creates an NSArray. If you want this array to be mutable, change the receiver of arrayWithObjects: to be NSMutableArray; if not, change the declaration to correctly identify this as an NSArray instead of an NSMutableArray.

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