C：不兼容的指针类型初始化 [英] C: Incompatible pointer type initializing

问题描述

我想学C.我目前在指针所以我决定写一些code，看看它是如何工作的。然而，code按预期工作（即它增加了一个字符-J在一个数组并打印在控制台上），但我得到有关兼容的指针赋值警告。我已经添加了警告，因为上线评论被警告中给出。

I'm trying to learn C. I'm currently on pointers so I've decided to write some code to see how it works. However the code works as intended (i.e. it adds chars a-j in an array and prints it on the console) but I'm get warnings about incompatible pointer assignment. I've added the warnings as comments on the lines were the warnings are given.

#include <stdio.h>
#include <stdlib.h>


int main(int argc, const char * argv[]) {

    #define MAX 10

    char* c[MAX]; // pointer to the 1st element in the array
    char* pointer = &c; // Warning: Incompatible pointer types initializing 'char *' with an expression of type 'char *(*)[10]'
    for (int j = 0; j < 10; j++)
    {
        *pointer = 'a' + j;
        pointer++;
    }

    pointer = &c; // Warning: Incompatible pointer types assigning to 'char *' from 'char *(*)[10]'
    for (int j = 0; j < 10; ++j)
    {
        printf("i[%d] = %c\n", j, *pointer);
        ++pointer;
    }

    return 0;
}

有人可以解释为什么我得到这些警告？

Can someone please explain why I'm getting these warnings?

char* pointer = &c; & pointer = &c;

据我所知，code我写如下声明一个字符指针称为指针和数组指针在分配1个元素的地址。

I understand the code I'm writing as follows declare a char pointer called pointer and assign the address of the 1st element in the array to the pointer.

PS！请不要在如何实现更好的书面code相同的结果，我想在这里了解指针和数组发表评论。因此，尽管这可能是实现这一结果的详细办法，我觉得这是语法正确的，所以如果我有这错了，请帮助我理解。

PS! please don't comment on how to achieve the same result with better written code as I'm trying to learn here about pointers and arrays. So while this may be a verbose way to achieve this result, I feel it is syntactically correct, so if I've got this wrong please help me understand.

推荐答案

修改

char* pointer = &c

到

char* pointer = c[0];

C 元素类型是的char * ，但和C 类型是一个指向 C 键入

c elements type is char * but &c type is a pointer to c type.

修改：这将解决您的警告，但问题是你第一次处理错误的类型

EDIT: This will fix your warning but the problem is you are dealing with the wrong types first.

而不是：

char* c[MAX];
char* pointer = &c;

使用：

char c[MAX];
char *pointer = c;

在你的程序你存储的字符，所以你需要字符的数组，而不是数组的char * 元素。

In your program you are storing characters, so you need an array of char and not an array of char * elements.

同为指针=和C; ，然后必须是指针= C;

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