我想使用java正则表达式查找所有以“#"开头的单词并以空格或“."结尾 [英] I want to find all words using java regex, that starts with "#" and ends with space or "."

问题描述

这是一个示例字符串

hi #myname, you  got #amount

我想使用 java regx 查找所有单词，以 # 开头并以空格或 结尾.示例 #myname,#amount

I want to find all words using java regx, that starts with # and ends with space or . example #myname,#amount

我尝试了以下正则表达式，但不起作用.

I tried the following Regex, but it doesn't work.

String regx = "^#(\\s+)";

推荐答案

这个应该是这样的:

#(\w+)(?:[, .]|$)

• # 与 # 字面匹配
• \w 是一个至少包含一个字母的单词
• (?:) 是非捕获组
• [, .]|$ 是包括行尾的结束字符集 $
• # matches # literally
• \w is a word with at least one letter
• (?:) is non-capturing group
• [, .]|$ is set of ending characters including the end of line $

有关详细信息，请查看 Regex101.

For more information check out Regex101.

在 Java 中不要忘记用双 \\ 转义:

In Java don't forget to escape with double \\:

String str = "hi #myname, you  got #amount";
Matcher m = Pattern.compile("#(\\w+)(?:[, .]|$)").matcher(str);
while (m.find()) {
   ...
}

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