Powershell将一个长数组分解为一行长度为N的数组? [英] Powershell break a long array into a array of array with length of N in one line?

问题描述

例如，给定一个列表 1,2,3,4,5,6,7,8,1,2,3,4,5,6,7,8 和一个数字4，它返回一个长度为4的列表的列表，即(1, 2, 3, 4), (5, 6, 7, 8), (1, 2, 3, 4), (5, 6, 7, 8).

For example, given a list 1,2,3,4,5,6,7,8,1,2,3,4,5,6,7,8 and a number 4, it returns a list of list with length of 4, that is (1, 2, 3, 4), (5, 6, 7, 8), (1, 2, 3, 4), (5, 6, 7, 8).

基本上我想在 Powershell 中实现以下 Python 代码.

Basically I want to implement the following Python code in Powershell.

s = 1,2,3,4,5,6,7,8,1,2,3,4,5,6,7,8
z = zip(*[iter(s)]*4)  # Here N is 4
# z is (1, 2, 3, 4), (5, 6, 7, 8), (1, 2, 3, 4), (5, 6, 7, 8)

以下脚本返回 17 而不是 5.

The following script returns 17 instead of 5.

$a = 1,2,3,4,5,6,7,8,1,2,3,4,5,6,7,8,0
$b = 0..($a.Length / 4) | % {  @($a[($_*4)..($_*4 + 4 - 1)]) } 
$b.Length

推荐答案

PS> $a = 1..16
PS> $z=for($i=0; $i -lt $a.length; $i+=4){ ,($a[$i]..$a[$i+3])}
PS> $z.count
4    

PS> $z[0]
1
2
3
4

PS> $z[1]
5
6
7
8

PS> $z[2]
9
10
11
12

PS> $z[3]
13
14
15
16

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