C ++：为什么int数组【尺寸】工作？ [英] C++: Why does int array[size] work?

问题描述

我已经开始学习C ++。我读了前可以在运行时设置运行和dymanic数组的数组的大小只能进行设置。所以，我期待这失败，但事实并非如此：

I have started learning c++. I read that an array's size can only be set before run and dymanic arrays can be set during runtime. So I was expecting this to fail but it didn't:

#include <iostream>

int main() {
    using namespace std;
    int size;
    cout << "enter array size:";
    cin >> size;
    int i, score[size], max; //array size set to variable doesn't fail
    cout << endl << "enter scores:\n";
    cin >> score[0];
    max = score[0];
    for (i = 1; i < size; i++)
    {
        cin >> score[i];
        if (score[i] > max)
    max = score[i];
    }
    cout << "the highest score is " << max << endl;
    return 0;
}

这是在最近C ++编译器中的新功能？它是实现我需要一个动态数组并创建呢？

Is this a new feature in recent C++ compilers? Is it realising I need a dynamic array and creating that instead?

推荐答案

也许你正在使用GCC编译器，它具有称为扩展的变长的数组。

Probably you are using GCC compiler, it has an extension called Arrays of Variable Length.

的std ::矢量是在真正的动态数组C ++。

std::vector is the real dynamic arrays in C++.

要选择GCC这个标准，使用选项-std = C ++ 11;获得所有标准所要求的诊断，你也应该（如果你想他们是错误，而不是警告或-pedantic-错误）指定-pedantic。

To select this standard in GCC, use the option -std=c++11; to obtain all the diagnostics required by the standard, you should also specify -pedantic (or -pedantic-errors if you want them to be errors rather than warnings).

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