int数组的最大尺寸？ [英] Maximum size of int array?

问题描述

可能重复：

我写了一个简单的程序。

I have written a simple program.

#include <iostream>

using namespace std;

int main(int argc, char* argv[])
{
    int genotype[150000000];
}

但我得到一个奇怪的错误：

But I get a strange error:

运行失败（退出值1，总时间：131ms）

RUN FAILED (exit value 1, total time: 131ms)

我保存这个金额 int ？

（我有足够的内存来保存 int s和我的计算机是64位）

(I have enough memory to save this amount of ints and my computer is 64-bit)

推荐答案

将这个放在堆上，使用new：

Your stack is too small. Put this on the heap, using new:

int* genotype = new int[150000000];

我希望以下内容有用。

已签署的字元：-127至127（请注意，不是-128至127;这里包含1的补充平台）

unsigned char：0 to 255 cybo
plain char：-127到127或0到255（取决于默认的char signedness）

signed short：-32767到32767

unsigned short：0到65535

signed int：-32767 to 32767

unsigned int：0 to 65535

signed long：-2147483647 to 2147483647

unsigned long：0 to 4294967295

signed long long：-9223372036854775807至9223372036854775807

unsigned long long：0 to 18446744073709551615

signed char: -127 to 127 (note, not -128 to 127; this accommodates 1's-complement platforms)
unsigned char: 0 to 255
"plain" char: -127 to 127 or 0 to 255 (depends on default char signedness)
signed short: -32767 to 32767
unsigned short: 0 to 65535
signed int: -32767 to 32767
unsigned int: 0 to 65535
signed long: -2147483647 to 2147483647
unsigned long: 0 to 4294967295
signed long long: -9223372036854775807 to 9223372036854775807
unsigned long long: 0 to 18446744073709551615

或者你可以使用limit.h来了解你的程序所依赖的。
例如，这将是如何找到int的最大范围：

Or you can use limit.h to find out around what your program relies on. For example, this is how you will find maximum range for int:

C：

#include <limits.h>
const int min_int = INT_MIN;
const int max_int = INT_MAX;

C ++

#include <limits>
const int min_int = std::numeric_limits<int>::min();
const int max_int = std::numeric_limits<int>::max();

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