“蟒蛇式"将一串逗号分隔的整数解析为整数列表的方法? [英] "pythonic" method to parse a string of comma-separated integers into a list of integers?

问题描述

我正在读取一串整数，例如 "3 ,2 ,6 " 并希望它们在列表 [3,2,6] 中作为整数.这很容易破解，但pythonic"的做法是什么?

I am reading in a string of integers such as "3 ,2 ,6 " and want them in the list [3,2,6] as integers. This is easy to hack about, but what is the "pythonic" way of doing it?

推荐答案

mylist = [int(x) for x in '3 ,2 ,6 '.split(',')]

如果您不确定是否只有数字(或想丢弃其他数字):

And if you're not sure you'll only have digits (or want to discard the others):

mylist = [int(x) for x in '3 ,2 ,6 '.split(',') if x.strip().isdigit()]

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