如何覆盖python列表中的init方法? [英] How do I override the init method in python list?

问题描述

我需要继承 list 类并覆盖 init() 方法以获取参数 a,b .a 应该是我初始化的列表的长度，b 应该是列表中项目之间的步骤.我只是不知道从哪里开始覆盖 init 方法.

I need to inherit list class and override the init() method to take parameters a,b . a should be the lenght of the list I initialise and b should the step between Items in the list. I just don't know where to start with overriding the init method.

def myclass(list):
    def __init__(a,b,*args, **kwargs):
         pass

我不知道该怎么办.

我已经看到我可以做到这一点:

I have seen I can do this:

class MyClass(list):
    def __init__(a,b):
        data =[x for x in range(0,a*b,b)]
        list.__init__(self,data)

但是我不熟悉python如何实现列表类，例如我如何使用我刚刚通过的列表理解.

But the I am not familiar with how python implements the list class, for instance how do I get to use the list comprehension I just passed.

推荐答案

感谢所有回复的人.意识到我可以通过这种方式实现我想要的:

Thanks to everyone who responded. Realised I could achieve what I wanted to this way:

class myclass(list):
    def __init__(self,a,b):
        data =[x for x in range(0,a*b,b)]
        self.length = len(data)
        super(myclass, self).__init__()
        self.extend(data)

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