Python:类型错误:“列表"对象不可在全局变量上调用 [英] Python: TypeError: 'list' object is not callable on global variable

问题描述

我目前正在使用 Python 编写基于文本的冒险作为学习练习.我希望帮助"成为一个全局命令，作为值存储在列表中，可以(基本上)随时调用.当玩家进入新房间或帮助选项发生变化时，我会使用新值重置 help_commands 列表.但是，当我调试以下脚本时，我得到一个 'list' object is not callable TypeError.

I am currently in the process of programming a text-based adventure in Python as a learning exercise. I want "help" to be a global command, stored as values in a list, that can be called at (essentially) any time. As the player enters a new room, or the help options change, I reset the help_commands list with the new values. However, when I debug the following script, I get a 'list' object is not callable TypeError.

我一遍又一遍地检查我的代码，似乎无法弄清楚出了什么问题.我对 Python 有点陌生，所以我认为这是我忽略的一些简单的事情.

I have gone over my code time and time again and can't seem to figure out what's wrong. I'm somewhat new to Python, so I assume it's something simple I'm overlooking.

player = {
    "name": "",
    "gender": "",
    "race": "",
    "class": "",
    "HP": 10,
}

global help_commands
help_commands = ["Save", "Quit", "Other"]

def help():
    sub_help = '|'.join(help_commands)
    print "The following commands are avalible: " + sub_help


def help_test():
    help = ["Exit [direction], Open [object], Talk to [Person], Use [Item]"]
    print "Before we go any further, I'd like to know a little more about you."
    print "What is your name, young adventurer?"
    player_name = raw_input(">> ").lower()
    if player_name == "help":
        help()
    else:
        player['name'] = player_name
        print "It is nice to meet you, ", player['name'] + "."

help_test()

你就像我的 Python 大师，Moses.这解决了我的问题，但是现在我无法让 help_commands 中的值被新命令覆盖:

You're like my Python guru, Moses. That fixed my problem, however now I can't get the values in help_commands to be overwritten by the new commands:

player = {
    "name": "",
    "gender": "",
    "race": "",
    "class": "",
    "HP": 10,
}

# global help_commands
help_commands = ["Save", "Quit", "Other"]

def help():
    sub_help = ' | '.join(help_commands)
    return "The following commands are avalible: " + sub_help


def help_test():
    print help()
    help_commands = ["Exit [direction], Open [object], Talk to [Person], Use [Item]"]
    print help()
    print "Before we go any further, I'd like to know a little more about you."
    print "What is your name, young adventurer?"
    player_name = raw_input(">> ").lower()
    if player_name == "help":
        help()
    else:
        player['name'] = player_name
        print "It is nice to meet you, ", player['name'] + "."

help_test()

想法?

推荐答案

您将列表的名称与函数的名称混在一起:

You are mixing the name of a list with that of a function:

help = ["Exit [direction], Open [object], Talk to [Person], Use [Item]"]

然后:

def help():
    sub_help = '|'.join(help_commands)
    print "The following commands are avalible: " + sub_help

当前作用域(引用列表)中的名称 help 被视为可调用的，事实并非如此.

The name help in the current scope (which references a list) is being treated as a callable, which is not the case.

考虑重命名列表或更好，两者兼而有之，因为名称 help 已被内置函数使用.

Consider renaming the list or better still, both, since the name help is already being used by a builtin function.

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