如何比较没有Java utils的两个字符串数组 [英] how to compare two string arrays without java utils

问题描述

检查是否数组ARR1包含在同一顺序的相同元素ARR2在java中。

Check to see if the array arr1 contain the same elements as arr2 in the same order in java.

例如：

    isTheSame({"1", "2", "3"}, {"1", "2", "3"}) → true
    isTheSame({"1", "2", "3"}, {"2", "1", "1"}) → false
    isTheSame({"1", "2", "3"}, {"3", "1", "2"}) → false

到目前为止，我有

so far i have

public boolean isTheSame(String[] arr1, String[] arr2)
{
   if (arr1.length == arr2.length)
   {
      for (int i = 0; i < arr1.length; i++)
       {
          if (arr1[i] == arr2[i])
          {
            return true;
          }
       }
    }
    return false;  
 }

这里的问题是，它只有比较两个阵列的第一个元素

The problem with this is that it only compares the first element of the two arrays.

推荐答案

您是迭代，直到找到一个匹配。您应该寻找一个字符串不匹配，你应该使用等于不是 ==

You are iterating until you find a match. You should instead be looking for a String which doesn't match and you should be using equals not ==

// same as Arrays.equals()
public boolean isTheSame(String[] arr1, String[] arr2) {
    if (arr1.length != arr2.length) return false;
    for (int i = 0; i < arr1.length; i++)
        if (!arr1[i].equals(arr2[i]))
            return false;
    return true;
}

FYI这是满足Arrays.equals不会因为它处理空值，以及

public static boolean equals(Object[] a, Object[] a2) {
    if (a==a2)
        return true;
    if (a==null || a2==null)
        return false;

    int length = a.length;
    if (a2.length != length)
        return false;

    for (int i=0; i<length; i++) {
        Object o1 = a[i];
        Object o2 = a2[i];
        if (!(o1==null ? o2==null : o1.equals(o2)))
            return false;
    }

    return true;
}

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