用 Scala 替换 List 中的元素 [英] Replace element in List with scala

问题描述

如何用不可变列表替换索引元素.

How do you replace an element by index with an immutable List.

例如

val list = 1 :: 2 ::3 :: 4 :: List()

list.replace(2, 5)

推荐答案

除了之前所说的，你还可以使用 patch 函数来替换一个序列的子序列:

In addition to what has been said before, you can use patch function that replaces sub-sequences of a sequence:

scala> val list = List(1, 2, 3, 4)
list: List[Int] = List(1, 2, 3, 4)

scala> list.patch(2, Seq(5), 1) // replaces one element of the initial sequence
res0: List[Int] = List(1, 2, 5, 4)

scala> list.patch(2, Seq(5), 2) // replaces two elements of the initial sequence
res1: List[Int] = List(1, 2, 5)

scala> list.patch(2, Seq(5), 0) // adds a new element
res2: List[Int] = List(1, 2, 5, 3, 4)

这篇关于用 Scala 替换 List 中的元素的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！