我如何比较两个数组，删除类似的项目，而不需要通过整个数组迭代？ [英] How can I compare two arrays, removing similar items, without iterating through the whole array?

问题描述

是否可以比较两个阵列和移除相等（如果它们是相同的索引）的值，而无需通过两个阵列迭代？下面是一个例子：

Is it possible to compare two arrays and remove the values that are equal (if they are at the same index), without iterating through both arrays? Here is an example:

$array1 = @(1,2,3,4,5,6,7,23,44)
$array2 = @(1,1,3,4,5,7,6,23,45)

$array3 = $sudo_compare_function $array1 $array2

其中， $ ARRAY3 现在将包含索引数组，其中 $数组2 是 $数组1 数组：

where $array3 would now contain an array of indexes where $array2 is different from $array1 array:

(1,5,6,8)

如果没有这样的事情，有没有一种简单的方法做同样的事情，而无需通过两个数组迭代？

If there isn't something like this, is there an easy way to do something similar without iterating through both arrays?

推荐答案

使用比较对象 cmdlet来获取不同值的数组：

Use the Compare-Object cmdlet to get an array of differing values:

$array1 = @(1,2,3,4,5,6,7,23,44)
$array2 = @(1,1,3,4,5,7,6,23,45)

$array3 = @(Compare-Object $array1 $array2 | select -Expand InputObject

有关比较只是相应的指标，你必须手动进行比较：

For comparing just the corresponding indexes you'll have to manually make the comparison:

function Compare-Indexes($a1, $a2) {
  $minindex = [math]::Min($a1.Length, $a2.Length)
  $maxindex = [math]::Max($a1.Length, $a2.Length)

  for ($i = 0; $i -le $minindex; $i++) {
    if ( $a1[$i] -ne $a2[$i] ) { $i }
  }
  for ( $i = $minindex + 1; $i -le $maxindex; $i++ ) { $i }
}

$array1 = @(1,2,3,4,5,6,7,23,44)
$array2 = @(1,1,3,4,5,7,6,23,45)

$array3 = Compare-Indexes $array1 $array2

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