当值为 SWIGTYPE 时如何将值传递给函数 [英] How to pass a value to a function when the value is SWIGTYPE

问题描述

我在java中有一个这样的包装函数:

I have a wrapped function in java like this:

dosomething(SWIGTYPE_sometypeSTRUCT STRUCTtype);

最初在 C 代码中，声明是这样的:

Originally in the C code, the declaration looks so:

dosomething(sometypeSTRUCT* structtype);

如何将 SWIGTYPE 传递给 java 函数.如果我做:SWIGTYPE_sometypeSTRUCT something = new SWIGTYPE_sometypeSTRUCT();

How can I pass the SWIGTYPE to the java function. if I do: SWIGTYPE_sometypeSTRUCT something = new SWIGTYPE_sometypeSTRUCT ();

它不起作用..只有当我设置 somthing = null 时它才会起作用.

it won't work.. It will work only if I set somthing = null.

推荐答案

问题是 SWIG 还没有看到 sometypeSTRUCT 的定义 - 据它所知dosomething 函数采用的指针是不透明类型.

The problem is that SWIG hasn't seen a definition of sometypeSTRUCT - as far as it knows the pointer your dosomething function takes is an opaque type.

当 SWIG 不知道细节时，它无法有意义地包装它，唯一安全的做法是让您使用此类类型在 C 中执行您可以执行的操作.

When SWIG doesn't know details it can't wrap it meaningfully and the only safe thing to do is let you do what you would be able to do in C with such a type.

要解决此问题，您可能希望使用 %include 引入结构的定义，或者可能在 SWIG 接口文件中提供定义.

To fix this you probably want to use %include to bring in the definition of the struct, or possibly provide a definition within the SWIG interface file.

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